题目链接 Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an inte…
Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an integer N…
A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 41995 Accepted Submission(s): 13502 Problem Description Given two integers n and m, count the number of pairs of integ…
A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25871 Accepted Submission(s): 8174 Problem Description Given two integers n and m, count the number of pairs of integ…
//2014.10.17 01:19 //题意: //先输入一个数N,然后分块输入,每块输入每次2个数,n,m,直到n,m同一时候为零时 //结束,当a和b满足题目要求时那么这对a和b就是一组 //注意: //每一块的输出中间有一个回车 A Mathematical Curiosity Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s…
#include<stdio.h> int main() { int N; int n,m; int a,b; int cas; scanf("%d",&N); while(N--) { cas=1;//必须在这儿初始化cas,坑 while(scanf("%d%d",&n,&m),n||m) { int count=0; for(a = 1; a < n; a++)//穷举法 { for(b = a + 1; b <…
题目:pid=1017">点击打开链接 #include<stdio.h> int main() { int t; scanf("%d",&t); while(t--) { int a=0; int m,n; while(scanf("%d%d",&n,&m)) { if(m==0&&n==0) break; a++; int i,j,k,z=0; for(i=1;i<n;i++) for(j…
Problem Description Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer. This problem contains multiple test cases! The first line of a multiple input is an integer N…