Herding】的更多相关文章

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1902    Accepted Submission(s): 540 Problem Description Little John is herding his father's cattles. As a lazy boy, he cannot tolerate chasing the…
hduoj 4706 Children's Day 2013 ACM/ICPC Asia Regional Online —— Warmup Herding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2005    Accepted Submission(s): 563 Problem Description Little Joh…
Herding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2418    Accepted Submission(s): 705 Problem Description Little John is herding his father's cattles. As a lazy boy, he cannot tolerate ch…
F - Herding Time Limit:1000MS       Memory Limit:32768KB      64bit IO Format:%I64d & %I64u Submit Status Description Little John is herding his father's cattles. As a lazy boy, he cannot tolerate chasing the cattles all the time to avoid unnecessary…
Herding Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1553 Accepted Submission(s): 440 Problem Description Little John is herding his father's cattles. As a lazy boy, he cannot tolerate chasing t…
Herding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 415    Accepted Submission(s): 59 Problem Description Little John is herding his father's cattles. As a lazy boy, he cannot tolerate chasi…
Herding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 937    Accepted Submission(s): 254 Problem Description Little John is herding his father's cattles. As a lazy boy, he cannot tolerate cha…
Herding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1125    Accepted Submission(s): 325 Problem Description Little John is herding his father's cattles. As a lazy boy, he cannot tolerate cha…
题意:给出N个点的坐标,从中取些点来组成一个多边形,求这个多边形的最小面积,组不成多边形的输出"Impossible"(测试组数 T <= 25, 1 <= N <= 100,  -1000 <= 坐标Xi, Yi <= 1000). 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4709 ——>>面积最小,若有的话,一定是三角形.判断3点是否能组成一个三角形,若用斜率来做,麻烦且可能会有精度误差…
题意:给出笛卡尔坐标系上 n 个点,n不大于100,求出这些点中能围出的最小面积. 可以肯定的是三个点围成的面积是最小的,然后就暴力枚举,计算任意三点围成的面积.刚开始是求出三边的长,然后求面积,运算步骤多,超时鸟~~,后来看了别人的代码,计算步骤挺少啊,不过我不会推这个式子. #include<stdio.h> #include<string.h> #include<math.h> struct node{ double x,y; }; node point[]; ;…