1035 Password (20 分)   To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero)…

PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642 题目描述: To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (o…

题目:http://pat.zju.edu.cn/contests/pat-a-practise/1035 分析:简单题.直接搜索,然后替换,不会超时,但是应该有更好的办法. 题目描述: To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

#include <stdio.h> #include <string.h> struct MyStruct { ]; ]; bool changed; }; int main() { int n,i,j; MyStruct User[]; while(scanf("%d",&n)!=EOF) { ;i<n;i++) User[i].changed=false; ; ;i<n;i++) { getchar(); scanf("%s…

problem To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in up…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

题意:给n个用户名和密码,把密码中的1改为@,0改为%,l改为L,O改为o. 让你输出需要修改密码的用户名个数,以及对应的用户名和密码,按输入的顺序.如果没有用户需要修改,则输出对应的语句,注意单复数... 没啥好说的,就for一遍密码,把需要改的改下,存入到ans中去. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cm…