hdu 5791 Two Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1421    Accepted Submission(s): 630 Problem Description Alice gets two sequences A and B. A easy problem comes. How many pair of sequ…

Man Down Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2030    Accepted Submission(s): 743 Problem Description The Game “Man Down 100 floors” is an famous and interesting game.You can enjoy t…

给出点集,和不大于L长的绳子,问能包裹住的最多点数. 考虑每个点都作为左下角的起点跑一遍极角序求凸包,求的过程中用DP记录当前以j为当前末端为结束的的最小长度,其中一维作为背包的是凸包内侧点的数量.也就是 dp[j][k]代表当前链末端为j,其内部点包括边界数量为k的最小长度.这样最后得到的一定是最优的凸包. 然后就是要注意要dp[j][k]的值不能超过L,每跑一次凸包,求个最大的点数量就好了. 和DP结合的计算几何题,主要考虑DP怎么搞 /** @Date : 2017-09-27 17:27…

Two 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5791 Description Alice gets two sequences A and B. A easy problem comes. How many pair of sequence A' and sequence B' are same. For example, {1,2} and {1,2} are same. {1,2,4} and {1,4,2} are not sam…

http://acm.hdu.edu.cn/showproblem.php?pid=5791 Two Problem Description   Alice gets two sequences A and B. A easy problem comes. How many pair of sequence A' and sequence B' are same. For example, {1,2} and {1,2} are same. {1,2,4} and {1,4,2} are not…

Two   Problem Description   Alice gets two sequences A and B. A easy problem comes. How many pair of sequence A' and sequence B' are same. For example, {1,2} and {1,2} are same. {1,2,4} and {1,4,2} are not same. A' is a subsequence of A. B' is a subs…

Two Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 889    Accepted Submission(s): 405 Problem Description Alice gets two sequences A and B. A easy problem comes. How many pair of sequence A' an…

题目描述: 求序列A,B的公共子序列个数: 基本思路: 想到了dp,选的状态也对,但是就是就是写不出状态转移方程,然后他们都出了,到最后我还是没出,很难受,然后主要是没有仔细考虑dp[i][j],dp[i][j-1],dp[i-1][j],dp[i-1][j-1]在A[ i]和B[i]在相同和不相同是的数量关系,我为啥就没想到要减呢,只想着怎么把他们加起来,着实智障: 定义状态dp[i][j]为序列A扫到i,序列B扫到B时候的公共子序列个数,状态转移方程如下: 其实这个状态转移方程也没那么好证明…

http://acm.split.hdu.edu.cn/showproblem.php?pid=5791 题意: 给出两个序列,求这两个序列的公共子序列的总个数. 思路: 和LCS差不多,dp[i][j]表示第一个的前i个和第二个的前j个所包含的公共子序列的个数. 首先考虑a[i]≠b[j]的情况,此时应该容易推得dp[i][j]=dp[i-1][j]+dp[i][j-1]-dp[i-1][j-1]. 那么当a[i]=b[j]时,i和j这两个字符可以单独组成一个公共序列,然后前面dp[i-1][…

B - Monkey and Banana Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1069 Appoint description: Description A group of researchers are designing an experiment to test the IQ of a monkey. They wi…