LeetCode----67. Add Binary(java)】的更多相关文章

题目描述: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 解题思路: 使用StringBuilder,且使用进位. 代码如下: public class Solution { public String addBinary(String a, String b) { String…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 题目标签:Math 题目给了我们两个string a 和 b,让我们把这两个二进制 相加. 首先把两个string 的长度得到,然后从右向左 取 两个string 的 digit. 增设一个 carry = 0: 每一轮把 digit…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 这个题目只要注意各种情况你就成功了一大半,特别要注意的是对进位赋值后可能产生的变化,以及最后一位进位为1时, 我们要把这个1插进来.同时注意字符串的低位是我们数值的高位 class Solution { public: string…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&qu…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 简单的二进制高精度加法. class Solution { public: string addBinary(string a, string b) { string ans=""; ,i=a.length()-,…
翻译 给定两个二进制字符串,返回它们的和(也是二进制字符串). 比如, a = "11" b = "1" 返回 "100". 原文 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 分析 我一開始写了这个算法,尽管实现…
Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 思路:二进制加法,比較简单.代码例如以下: public class Solution { public String addBinary(String a, String b) { int len = Math.max(a.l…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
题意:两个二进制数相加,大数加法的变形 大数加法流程: 1.倒置两个大数,这一步能使所有大数对齐 2.逐位相加,同时进位 3.倒置两个大数的和作为输出 class Solution { public: string addBinary(string a, string b) { if(a.size() < b.size()){ string t = a; a = b; b = t; } //该步使的能大数加小数,使其能加 reverse(a.begin(),a.end()); reverse(b…
原题链接 思路: 用一个数保存进制,从后往前不断pop出两个数字和进制数相加,放入返回值中. var addBinary = function(a, b) { var arrA = a.split(''); var arrB = b.split(''); var len = Math.max(a.length, b.length), c = 0, result = ''; while(len-- > 0 || c > 0) { let va = arrA.pop(); let vb = arr…
这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…
67. Add Binary Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". public class Solution { public String addBinary(String a, String b) { String res =""; int l1…
1.题目 67. Add Binary——easy Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1"Output: "100"Example 2:…
1 题目 Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 接口 String addBinary(String a, String b) 2 思路 处理二进制求和和进位.从低位开始,一直相加并且维护进位.和Add Two Numbers的区别是这个题目低位在后面,所以要从strin…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 BigInteger类 模拟加法 日期 题目地址:https://leetcode.com/problems/add-binary/description/ 题目描述 Given two binary strings, return their sum (also a binary string). The input strings are bot…
Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 解题思路: JAVA实现如下: static public String addBinary(String a, String b) { if (a.length() < b.length()) { String temp…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". (二)解题 题意很简单,实现二进制加法逻辑…
题目: Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 提示: 此题我的第一反应是把输入的两个字符串转化为数字,相加以后再把结果转化为二进制输出,但是测试用例中会有很大的输入,此时即使是long long型也会造成溢出,所以只能用最传统的由低位到高位逐位相加的方法去做. 代码: c…
二进制加法 https://discuss.leetcode.com/topic/33693/another-simple-java public String addBinary(String a, String b) { if(a==null||b==null){ return a==null?b:a; //如果其中一个为null,则返回另一个:结合着if条件语句可以包括两个都是null的情形 } int alen = a.length()-1; int blen = b.length()-…
class Solution(object):    def addBinary(self, a, b):        """        :type a: str        :type b: str        :rtype: str        """        resA=int(a,base=2)        resB=int(b,base=2)                sumAB=bin(resA+resB)   …
package addBinary67;/* Given two binary strings, return their sum (also a binary string).For example,a = "11"b = "1"Return "100". */public class Solution { public static String addBinary(String a, String b) { //ensure a.lengt…
题目简述: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 解题思路: class Solution: # @param a, a string # @param b, a string # @return a string def addBinary(self, a, b)…
题目: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 思路: 题意:对字符串的二进制数字,计算 把二进制转化为整数,设置变量carry位进位,sum%2,是相应的数字,carry = sum/2 - 代码: public class Solution { public St…
问题描述 问题分析 分析题意,此题实际是求解两个二进制数的和,但是有两点要注意: 1.字符串的长度不限,所以相应十进制数值很可能会超过int的上限. 2.二进制的加法规则是自右向左进位,需要注意,以题目示例为例: 11 +  1 ------ 100 所以直接将二进制字符串转成十进制值相加求和,再将十进制和转为二进制字符串的做法是不被接受的,虽然其复杂度只有O(1),错误做法如下: public class Solution { public string AddBinary(string a,…
Given two binary strings, return their sum (also a binary string). The input strings are both non-empty and contains only characters 1 or 0. Example 1: Input: a = "11", b = "1" Output: "100" Example 2: Input: a = "1010&q…
这个题目相对有点奇怪,题目如下: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 可能是我思路的问题吧,我之前是在考虑先将string转成int或者double,然后将二进制转为十进制进行计算,最后再将这个十进制转为二进制再转为string返回.这个思路本来是没问题的.但是.…
public class Solution { public String addBinary(String a, String b) { char[] aa=a.toCharArray(); char[] bb=b.toCharArray(); int size=aa.length>=bb.length?aa.length:bb.length; int[] mm=new int[size]; int c=0; int i=aa.length-1,j=bb.length-1,k=size-1;…