HDU - 1403 - Longest Common Substring】的更多相关文章

http://acm.hdu.edu.cn/showproblem.php?pid=1403 Longest Common Substring Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3068    Accepted Submission(s): 1087 Problem Description Given two string…
先上题目: Longest Common Substring Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4010    Accepted Submission(s): 1510 Problem Description Given two strings, you have to tell the length of the Long…
Description Given two strings, you have to tell the length of the Longest Common Substring of them. For example:str1 = bananastr2 = cianaic So the Longest Common Substring is "ana", and the length is 3. Input The input contains several test case…
http://acm.hdu.edu.cn/showproblem.php?pid=1403 题意:给出两个字符串,求最长公共子串的长度. 思路: 刚开始学后缀数组,确实感觉很难,但是这东西很强大,所以必须要学会它,推荐罗穗骞大牛的论文. #include<iostream> #include<algorithm> #include<cstring> #include<cstdio> #include<vector> #include<st…
hdu题目 poj题目 参考了 罗穗骞的论文<后缀数组——处理字符串的有力工具> 题意:求两个序列的最长公共子串 思路:后缀数组经典题目之一(模版题) //后缀数组sa:将s的n个后缀从小到大排序后将 排序后的后缀的开头位置 顺次放入sa中,则sa[i]储存的是排第i大的后缀的开头位置.简单的记忆就是“排第几的是谁”. //名次数组rank:rank[i]保存的是suffix(i){后缀}在所有后缀中从小到大排列的名次.则 若 sa[i]=j,则 rank[j]=i.简单的记忆就是“你排第几”…
后缀数组的买1送2题... HDU的那题数据实在是太水了,后来才发现在COJ和POJ上都是WA..原因在一点:在建立sa数组的时候里面的n应该是字符串长度+1....不懂可以去看罗大神的论文... 就是利用后缀数组模板求最长公共子串. #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<string> #include<cmat…
题目链接 题意 问两个字符串的最长公共子串. 思路 加一个特殊字符然后拼接起来,求得后缀数组与\(height\)数组.扫描一遍即得答案,注意判断起始点是否分别在两个串内. Code #include <bits/stdc++.h> #define maxn 200010 using namespace std; typedef long long LL; int a[maxn], wa[maxn], wb[maxn], wv[maxn], wt[maxn], h[maxn], rk[maxn…
后缀数组2倍增可解. #include <cstdio> #include <cstring> #include <cstdlib> #define MAXM 28 #define MAXN 100010 ]; ]; ]; ]; char s[MAXN]; ], sa[MAXN*]; ], rank[MAXN*]; bool cmp(int *r, int a, int b, int l) { return r[a]==r[b] && r[a+l]==r…
地址:http://acm.split.hdu.edu.cn/showproblem.php?pid=1403 题目: Longest Common Substring Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6296    Accepted Submission(s): 2249 Problem Description Give…
LCS2 - Longest Common Substring II A string is finite sequence of characters over a non-empty finite set Σ. In this problem, Σ is the set of lowercase letters. Substring, also called factor, is a consecutive sequence of characters occurrences at leas…