Codeforces E - Connected Components?】的更多相关文章

E - Connected Components? 思路: 补图bfs,将未访问的点存进set里 代码: #include<bits/stdc++.h> using namespace std; #define ll long long #define pb push_back #define mem(a,b) memset(a,b,sizeof(a)) ; bool vis[N]; int head[N]; int a[N]; ,ans=; struct edge{ int to,next;…
Description 题库链接 给你一个 \(n\) 个点 \(m\) 条边的无向图,求其补图的连通块个数及各个连通块大小. \(1\leq n,m\leq 200000\) Solution 参考了 ww140142 的做法.题解也转自该博客. 每次枚举一个未处理过的点,然后从它开始宽搜出它所在的连通块: 具体是枚举它的所有原图的边,标记起来,枚举边之后再枚举所有的点,将未标记的点加入该连通块,并加入队列继续宽搜: 为了节约无用的枚举,我们还需要对所有点构建链表,将已经在某个块内的点删除:…
很有意思的一道并查集  题意:给你n个点(<=500个),m条边(<=10000),q(<=20000)个询问.对每个询问的两个值xi yi,表示在从m条边内删除[xi,yi]的边后连接剩下的边,最后求连通块的总个数 求连通块的个数很容易想到并查集,即把每两块并在一起(祖先任选),可以相连就减一.但是每次询问最多需要m次维护.而某两个点可能直接或间接相连多遍,所以删边后此边上的两个点就不一定不相连(离线莫队处理失败).但是我们可以看点数并不多,所以关键从从点入手.  模拟前缀和,并以空间…
题目链接 题意 对给定的一张图,求其补图的联通块个数及大小. 思路 参考 ww140142. 维护一个链表,里面存放未归入到任何一个连通块中的点,即有必要从其开始进行拓展的点. 对于每个这样的点,从它开始进行 \(bfs\),将未被拓展到的点加入队列,并从链表中删除. 注意:写法上有一点要注意, 在处理完一整个连通块之后,记录下下一个连通块中的第一个点之后,再将最初的 \(src\) 从链表中删除.若一开始便删除,则会造成链表脱节. Code #include <bits/stdc++.h>…
E. Connected Components? time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given an undirected graph consisting of n vertices and  edges. Instead of giving you the edges that exist i…
Discription You are given an undirected graph consisting of n vertices and  edges. Instead of giving you the edges that exist in the graph, we give you m unordered pairs (x, y) such that there is no edge between x and y, and if some pair of vertices…
E. Connected Components? You are given an undirected graph consisting of n vertices and edges. Instead of giving you the edges that exist in the graph, we give you m unordered pairs (x, y) such that there is no edge between x and y, and if some pair…
Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0          3 |          | 1 --- 2    4 Given n = 5 and…
Write a program to find the strongly connected components in a digraph. Format of functions: void StronglyConnectedComponents( Graph G, void (*visit)(Vertex V) ); where Graph is defined as the following: typedef struct VNode *PtrToVNode; struct VNode…
原题链接在这里:https://leetcode.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected com…
We will learn how to use withRouter() to inject params provided by React Router into connected components deep in the tree without passing them down all the way down as props. The app component itself does not really use filter. It just passes the fi…
Number of Connected Components in an Undirected Graph Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1:…
Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0          3 |          | 1 --- 2    4 Given n = 5 and…
Write a function to count the number of connected components in a given graph. Format of functions: int CountConnectedComponents( LGraph Graph ); where LGraph is defined as the following: typedef struct AdjVNode *PtrToAdjVNode; struct AdjVNode{ Verte…
[抄题]: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: Input: n = 5 and edges = [[0, 1], [1, 2], [3, 4]…
原题链接在这里:https://leetcode.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目: Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected com…
Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: Input: n = 5 and edges = [[0, 1], [1, 2], [3, 4]] 0 3…
Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: | | --- Given n = 5 and edges = [[0, 1], [1, 2], [3, 4…
spark最新版公布了.之前的版本号就已经集成了graphx,这个版本号还改了一些bug. 我做了简单測试,只是网上关于集群模式执行spark资料太少了,仅仅有关于EC2(见參考资料1)的.可是还非常旧,好多命令都有变化了.非常讨厌写安装类的博客不注明当前使用软件的版本号,这是常识好不好?! 我的平台配置: spark:0.9.1 scala:2.10.4 hadoop:1.0.4 jdk:1.7.0 master node:1 worker node:16 1. spark 0\.9\.1的部…
We already know of the large corporation where Polycarpus works as a system administrator. The computer network there consists of n computers and m cables that connect some pairs of computers. In other words, the computer network can be represented a…
Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), write a function to find the number of connected components in an undirected graph. Example 1: 0        3 |          | 1 --- 2    4 Given n = 5 and e…
292D - Connected Components D. Connected Components time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output We already know of the large corporation where Polycarpus works as a system administrato…
D. Connected Components 题意 现在有n个点,m条编号为1-m的无向边,给出k个询问,每个询问给出区间[l,r],让输出删除标号为l-r的边后还有几个连通块? 思路 去除编号为[l,r]的边后,只剩下了[1,l-1]&&[r+1,m]两部分. 我们维护一个前缀以及后缀并查集,询问的时候把这两部分的边合并一下,就可以求出连通块的个数. 精辟! 代码 #include<bits/stdc++.h> #include<vector> #include…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 并查集 日期 题目地址:https://leetcode-cn.com/problems/number-of-connected-components-in-an-undirected-graph/ 题目描述 Given n nodes labeled from 0 to n - 1 and a list of undirected edges (ea…
一.题目 二.题目链接 http://codeforces.com/contest/920/problem/E 三.题意 给定一个$N$和$M$.$N$表示有$N$个点,$M$表示,在一个$N$个点组成的无向完全图中,接下来的$M$条无向边不存在. 问你在这个图中有多少个连通分量,并且从小到大输出每个连通分量的顶点个数. 四.思路 求无向图的连通分量个数,只需要跑一边bfs就OK了.其实dfs也可以,只是太多的“函数压栈现场保护”浪费一丢丢时间而已,慢一点点,影响其实并不大. 要注意的是,无论跑…
https://codeforces.com/contest/920/problem/E https://www.luogu.org/problemnew/show/P3452 https://www.lydsy.com/JudgeOnline/problem.php?id=1098 CF貌似出了原题? 这几个都是一样的,输入输出都一样,就是读入一张图,要求补图的连通块个数以及各个连通块大小 可以这样搞:维护一个set表示所有当前没到过的点:一开始所有点加进去 取出set中任意点作为起始点并从s…
题 OvO http://codeforces.com/contest/920/problem/E 解 模拟一遍…… 1.首先把所有数放到一个集合 s 中,并创建一个队列 que 2.然后每次随便取一个数,并且从集合中删除这个数,将这个数放入 que 3.取 que 首元素,记为 now,然后枚举集合 s,每次找到 s 中和 now 相连的元素 x,从 s 中删除元素 x,并且把 x 放入 que 中. 4.如果 s 不为空,回到步骤2 可见就是一个模拟,至于复杂度,计算如下. 由于每个数字只会…
#include <algorithm> #include <cstdio> #include <iostream> #include <queue> #include <set> using namespace std; const int N = 2e5 + 5; vector<int> result; std::set<pair<int, int> > unExistedMap; int nextPoin…
大意:给定无向图, 求补图的连通块数 bfs模拟即可, 这里用了map存图, set维护未划分的点集, 复杂度$O(nlog^2n)$, 用链表的话可以$O(n)$ #include <iostream> #include <algorithm> #include <cstdio> #include <set> #include <map> #include <queue> #define REP(i,a,n) for(int i=a…
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] bfs. 用一个链表来记录哪些点已经确定在某一个联通快里了. 一开始每个点都能用. 然后从第一个点开始进行bfs. 然后对于它的所有连接着的点(输入的图的补图 看看它是不是之前进行过bfs,如果是的话.就跳过.(可以用链表直接跳过.即沿着链表枚举它的出度. 否则.把这个点从链表中删掉.然后把这个点加入队列.继续bfs即可. 这样已经确定联通了的点之间不会再访问. 链表加速了寻找某个点的出度的过程. 且由于当n很大的时候.m只有2…