Description 给定一个长度为 \(n\) 的数列 \(a\) ,你可以任意选择一个区间 \([l,r]\) ,并给区间每个数加上一个整数 \(k\) ,求这样一次操作之后数列中最多有多少个数等于 \(c\). \(n,c,a_i\leq 10^5\) Solution 假设当前选择区间的右端点为 \(r\),那我们要强制将 \(a_r\) 这个元素变为 \(c\),不然可以通过让右端点 \(-1\) 使答案变得不劣. 同理,如果我们左端点 \(l\) 的元素 \(a_l\) 也要让其强…

题目大意: \(给你n个数a_i,给定一个m,你可以选择一个区间[l,r],让他们区间加一个任意数,然后询问一次操作完之后,最多能得到多少个m\) QWQ 考场上真的** 想了好久都不会,直到考试快结束才知道怎么做. 首先,根据题目,我们可以得知,假设我们修改了\([l,r]\)这个区间,那么最后的\(ans\)就应该是总的m的个数,减去区间中m的个数,加上区间内的众数的个数 QWQ 那么我们考虑怎么来处理这个. 首先,每个数字之间都是独立的. 所以我们可以预处理每一个数字出现的位置. 然后假设…

E. Increasing Frequency 题目链接:https://codeforces.com/contest/1082/problem/E 题意: 给出n个数以及一个c,现在可以对一个区间上的数同时加上或减去一个值,问最后c的最多数量为多少. 题解: 这题挺有意思的,我们通过分析题目可以发现,对于每一个d,如果把[l,r]里面的d都变为c,则最后c的数量为cnt(c,1,l-1)+cnt(c,r+1,n)+cnt(d,l,r). 这个式子变化一下,有:cnt(c,1,n)+cnt(d,…

You are given array a a of length n n . You can choose one segment [l,r] [l,r] (1≤l≤r≤n 1≤l≤r≤n ) and integer value k k (positive, negative or even zero) and change a l ,a l+1 ,…,a r  al,al+1,…,ar by k k each (i.e. a i :=a i +k ai:=ai+k for each l≤i≤…

题目链接 \(Description\) 给定\(n\)个数.你可以选择一段区间将它们都加上或减去任意一个数.求最终序列中最多能有多少个数等于给定的\(C\). \(n\leq5\times10^5\). \(Solution\) 先记一个表示\(C\)的个数的前缀和\(sum_i\). 选择修改的区间\([l,r]\)一定满足\(A_l=A_r\)且都是由\(A_l\)变成\(C\).所以我们枚举右端点,对每种权值单独考虑. 那么\(A_r\)要么是由前面某个等于\(A_r\)的数转移过来,要…

题目传送门 题意:给你n个数和一个c, 现在有一个操作可以使得 [ l, r ]区间里的所有数都加上某一个值, 现在问你c最多可以是多少. 题解: pre[i] 代表的是 [1,i] 中 c 的个数是多少. suf[i] 代表的是 [i,n] 中 c 的个数是多少. 我们可以处理出这些信息. 然后我们从后往前处理信息. 现在给定一个b[x], b[x] 记录的是 [l, r] 中 x 的个数 + [r+1, n] 中 c的个数. 那么 每次出现一个新的 x, 现在可以转移到b[x]的状态是 ma…

传送门 解题思路 贪心.对于一段区间中,可以将这段区间中相同的元素同时变成\(c\),但要付出的代价是区间中等于\(c\)的数的个数,设\(sum[i]\)表示等于\(c\)数字的前缀和,Max[i]表示数字\(i\)的最大个数.那么只要\(O(n)\)的扫一遍,维护一下每个数字的\(max\),具体做法是看一下\(Max[a[i]]\)大还是\(sum[i]\)大,如果\(sum\)大的话,说明前面都不变,直接把\(Max\)赋值成\(sum[i]+1\),否则直接让\(Max[i]++\),…

CF1082A Vasya and Book 模拟一下即可 \(Code\ Below:\) #include <bits/stdc++.h> using namespace std; const int inf=0x3f3f3f3f; int n,x,y,d,ans; int main() { int T; scanf("%d",&T); while(T--){ scanf("%d%d%d%d",&n,&x,&y,&am…

Frequency Hopping Time Limit: 10000ms Memory Limit: 131072KB This problem will be judged on UVA. Original ID: 1124864-bit integer IO format: %lld      Java class name: Main 20th July, 1942 Colonel Al Pacheno,According to the previous order “ref:   23…

BioInf-Wuerzburg/proovread - Github 主要是来解读 proovread 发表的文章,搞清楚它内在的原理. Proovread,这个工具绝对没有你想的那么简单,它引入了很多局部模型,而且在总体设计上也是很有眼光的. 原文:proovread: large-scale high-accuracy PacBio correction through iterative short read consensus 摘要 动机:目前边合成边测序的二代技术占主导,虽然准,但太…

1.第一次感觉MS也有这么难用的MFC类: 2.CFtpFileFind类只能实例化一个,多个实例同时查找会出错(因此下载时不能递归),采用队列存储目录再依次下载: 3.本程序支持文件夹嵌套上传下载: 4.boost::filesystem::create_directory不能递归创建文件夹,需手动实现 5.同时支持文件夹先打包压缩再上传功能(m_bZibFlag控制是否压缩) 代码如下: CFtpClient.h #ifndef __ftp_client_h__ #define __ftp_…

D. Maximum Diameter Graph 题意 给出每个点的最大度,构造直径尽可能长的树 思路 让度数大于$1$的点构成链,考虑是否能在链的两端加度为$1$的点 代码 #include <bits/stdc++.h> #define DBG(x) cerr << #x << " = " << x << endl; const int maxn = 1e3+5; using namespace std; typedef…

原table2excel代码 /* * 采用jquery模板插件——jQuery Boilerplate * * Made by QuJun * 2017/01/10 */ //table2excel.js ; (function ($, window, document, undefined) { var pluginName = "table2excel", rootPath = "http://" + window.location.host, current…

A. Vasya and Book Solved. 三种方式取$Min$ #include <bits/stdc++.h> using namespace std; #define ll long long #define INF 0x3f3f3f3f3f3f3f3f int t; ll n, x, y, d; ll calc(ll x) { ? x / d : x / d + ; } int main() { scanf("%d", &t); while (t--…

A. Vasya and Book 简单的取余运用. #include <iostream> #include <cstdio> #include <limits.h> #include <math.h> using namespace std; const int INF = INT_MAX; int main(){ int T; scanf("%d", &T); while(T--){ int n, x, y, d; scan…

http://www.practice.geeksforgeeks.org/problem-page.php?pid=493 Sorting Elements of an Array by Frequency Given an array of integers, sort the array according to frequency of elements. For example, if the input array is {2, 3, 2, 4, 5, 12, 2, 3, 3, 3,…

原题链接在这里:https://leetcode.com/problems/number-of-longest-increasing-subsequence/description/ 题目: Given an unsorted array of integers, find the number of longest increasing subsequence. Example 1: Input: [1,3,5,4,7] Output: 2 Explanation: The two longe…

BACKGROUND OF THE INVENTION Mobile devices, such as but not limited to personal data appliances, cellular phones, radios, pagers, lap top computers, and the like are required to operate for relatively long periods before being recharged. These mobile…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…

Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array. Formally the function should: Return true if there exists i, j, k such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return…

Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). E…

Given an unsorted array of integers, find the length of longest increasing subsequence. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than…

Write a bash script to calculate the frequency of each word in a text file words.txt. For simplicity sake, you may assume: words.txt contains only lowercase characters and space ' ' characters. Each word must consist of lowercase characters only. Wor…

error: unable to rewind rpc post data - try increasing http.postBuffererror: RPC failed; curl 56 Recv failure: Connection was abortedfatal: The remote end hung up unexpectedly 当使用git 一次提交的数据过大时,会出现以上错误,按照提示我们增大postBuffer git config --global http.post…

1. Description Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array. Formally the function should: Return true if there exists i, j, k such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤…

Longest Increasing Subsequence(LIS) 一个美丽的名字 非常经典的线性结构dp [朴素]:O(n^2) d(i)=max{0,d(j) :j<i&&a[j]<a[i]}+1 直接两个for [二分查找优化]:O(n^2) g(i):d值为i的最小的a  每次更新然后lower_bound即可 ［大于等于］ lower_boundReturn iterator to lower bound Returns an iterator pointing…

Given a sequence of integers, find the longest increasing subsequence (LIS). You code should return the length of the LIS. Have you met this question in a real interview?     Example For [5, 4, 1, 2, 3], the LIS  is [1, 2, 3], return 3 For [4, 2, 4,…

Given a sequence of integers, find the longest increasing subsequence (LIS). You code should return the length of the LIS. Example For [5, 4, 1, 2, 3], the LIS  is [1, 2, 3], return 3 For [4, 2, 4, 5, 3, 7], the LIS is [4, 4, 5, 7], return 4 Challeng…

题目: Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'…

Given a string, sort it in decreasing order based on the frequency of characters. Example 1: Input: "tree" Output: "eert" Explanation: 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Th…