Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…

343. Integer Break Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, r…

lc 343 Integer Break 343 Integer Break Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 +…

Week 11 - 343.Integer Break Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 数学解法 动态规划 日期 题目地址:https://leetcode.com/problems/integer-break/description/ 题目描述 Given a positive integer n, break it into the sum of at least two positive integers and maximize…

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. Example 1: Input: 2 Output: 1 Explanation: 2 = 1 + 1, 1 × 1 = 1. Example 2: Input:…

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…

https://leetcode.com/problems/integer-break/ Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2…

问题描述: Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10…

题目:Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3…

给定一个正整数 n,将其拆分为至少两个正整数的和,并使这些整数的乘积最大化. 返回你可以获得的最大乘积.例如,给定 n = 2,返回1(2 = 1 + 1):给定 n = 10,返回36(10 = 3 + 3 + 4).注意:你可以假设 n 不小于2且不大于58. 详见:https://leetcode.com/problems/integer-break/description/ C++: class Solution { public: int integerBreak(int n) { i…

要求 给定一个正数n,可将其分割成多个数字的和,求让这些数字乘积最大的分割方法(至少分成两个数) 示例 n=2,返回1(2=1+1) n=10,返回36(10=3+3+4) 实现 回溯遍历(n^2,超时) 1 class Solution { 2 private: 3 int max3( int a , int b , int c ){ 4 return max( a , max(b,c) ); 5 } 6 7 // 将n进行分割(至少两部分)可获得的最大乘积 8 int breakIntege…

343. 整数拆分 343. Integer Break 题目描述 给定一个正整数 n,将其拆分为至少两个正整数的和,并使这些整数的乘积最大化. 返回你可以获得的最大乘积. 每日一算法2019/5/28Day 25LeetCode343. Integer Break 示例 1: 输入: 2 输出: 1 解释: 2 = 1 + 1, 1 × 1 = 1. 示例 2: 输入: 10 输出: 36 解释: 10 = 3 + 3 + 4, 3 × 3 × 4 = 36. 说明: 你可以假设 n 不小于…

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…

题目: Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 =…

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 +…

A typical CS style DP based solution: class Solution(object): def __init__(self): self.hm = {} def integerBreak(self, n): if n in self.hm: return self.hm[n] ret = 0 for i in range(1, n//2 + 1): v1 = self.integerBreak(i) v2 = self.integerBreak(n - i)…

Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. Example 1: Input: 2 Output: 1 Explanation: 2 = 1 + 1, 1 × 1 = 1. Example 2: Input:…

Question Given a positive integer n, break it into the sum of at least two positive integers and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (…

题目链接:https://leetcode.com/problems/integer-break/description/ 题目大意:给定一个自然数,将其分解,对其分解的数作乘积,找出最大的乘积结果.例子如下: 法一(借鉴):dp,一维dp,dp[i]表示i的最大分解结果的乘积,而dp[5]可以dp[4],dp[3],dp[2],dp[1]为基础,dp[4]可以dp[3],dp[2],dp[1]为基础,代码如下(耗时1ms): //dp[i]表示给定i分解后能得到的最大乘积值 public in…

思路: 将n不断拆分3出来直至其小于或等于4. 实现: class Solution { public: int integerBreak(int n) { ] = {, , , }; ) return a[n]; ; ) { p *= ; n -= ; } return p * n; } };…

**322. Coin Change 思路:动态规划,构造一个数组,存入当前index最少需要多少个coin public int coinChange(int[] coins, int amount) { if(coins == null || coins.length == 0 || amount <= 0) return 0; //表示Index需要多少个coin int[] dp = new int[amount + 1]; for(int i = 1; i < amount + 1;…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

2. Add Two Numbers https://leetcode.com/problems/add-two-numbers/description/ class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode result(-); ListNode* current = &result; ; while(l1!=NULL || l2!=NULL){ ; ; if(l1!=NU…

由于之前对算法题接触不多,因此暂时只做easy和medium难度的题. 看完了<算法(第四版)>后重新开始刷LeetCode了,这次决定按topic来刷题,有一个大致的方向.有些题不止包含在一个topic中,就以我自己做的先后顺序为准了. Array ---11.Container With Most Water 给定许多条与y轴平行的直线,求其中两条直线与x轴围成的容器的最大容量. 这道题用到了双指针的思想.我们在数轴的两端分别放置一个left指针和right指针,因为容器容量=较短边*两边…

［抄题］: 给出三个字符串:s1.s2.s3,判断s3是否由s1和s2交叉构成.(洗牌) 比如 s1 = "aabcc" s2 = "dbbca" - 当 s3 = "aadbbcbcac",返回  true. - 当 s3 = "aadbbbaccc", 返回 false. ［思维问题］: 不知道怎么表示交叉.分析要用三维数组,i j k.但是分析j 是否等于i+j,就只用二维数组了. 不知道为什么看最后一位:第一位不知道是…

算法思想 二分查找 贪心思想 双指针 排序 快速选择 堆排序 桶排序 搜索 BFS DFS Backtracking 分治 动态规划 分割整数 矩阵路径 斐波那契数列 最长递增子序列 最长公共子系列 0-1 背包 数组区间 字符串编辑 其它问题 数学 素数 最大公约数 进制转换 阶乘 字符串加法减法 相遇问题 多数投票问题 其它 数据结构相关 栈和队列 哈希表 字符串 数组与矩阵 1-n 分布 有序矩阵 链表 树 递归 层次遍历 前中后序遍历 BST Trie 图 位运算 参考资料 算法思想 二…

357. Count Numbers with Unique Digits 解题思路: 用arr[i]存放长度为i时,各位互不相同的数字的个数,所以arr[1]=10,arr[2]=9*9.(第一位要为1,第二位与第一位要不同) arr[3] = arr[2]*8,所以arr[i]=arr[i-1]*(10 - (k-1)).之后求和就可以了. int countNumbersWithUniqueDigits(int n) { if (!n) return 1; if (n == 1) retu…