UVA.10305 Ordering Tasks 题意分析 详解请移步 算法学习 拓扑排序(TopSort) 拓扑排序的裸题 基本方法是,indegree表示入度表,vector存后继节点.在topsort函数中,制造一个辅助队列,首先从入度表中找到入度为0的点作起点,并且置入度为-1.接着依次处理队列中的节点,首先根据他们的后继,将其后继节点的入度依次减1,若其后继节点中的入度存在-1的,说明成环,则不存在拓扑排序.紧接着再从入度表中找到入度为0的节点,加入到队列中,直到队列空.当退出whil…

M - Ordering Tasks Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Description John has n tasks to do. Unfortunately, the tasks are not independent and the execution of one task is only possible if other tasks have already been…

John has n tasks to do. Unfortunately, the tasks are not independent and the execution of one task is only possible if other tasks have already been executed. Input The input will consist of several instances of the problem. Each instance begins with…

John has n tasks to do. Unfortunately, the tasks are not independent and the execution of one task isonly possible if other tasks have already been executed.InputThe input will consist of several instances of the problem. Each instance begins with a…

今天刚学的拓扑排序,大概搞懂后发现这题是赤裸裸的水题. 于是按自己想法敲了一遍,用queue做的,也就是Kahn算法,复杂度o(V+E),调完交上去,WA了... 于是检查了一遍又交了一发,还是WA... 我还以为是用queue的问题,改成stack也WA,然后干脆放弃STL,手敲了队列,还是WA了... 我抓狂了. 感觉没什么问题的,卡了我一个多小时.最后用样例0 1测试,发现是在输入的循环判断时出错了,他要求两个都为0时结束,我只要有一个为0就结束了... 坑爹,血的教训... 然后我把之前…

题目链接: https://vjudge.net/problem/UVA-10305#author=goodlife2017 题目描述 John有n个任务,但是有些任务需要在做完另外一些任务后才能做. 输入 输入有多组数据,每组数据第一行有两个整数1 <= n <= 100 和 m.n是任务个数(标记为1到n),m两个任务直接关系的数量.在此之后,有m行,每行有2个整数i和j,代表任务i必须在任务j之前完成.用n = m = 0结束整个输入. 输出 每一个数据对应一行n个整数,代表任务完成的顺…

本文链接:http://www.cnblogs.com/Ash-ly/p/5398586.html 题意: 假设有N个变量,还有M个二元组(u, v),分别表示变量u 小于 v.那么.所有变量从小到大排列起来应该是什么样子的呢?例如,有四个变量a,b,c,d,若a < b, c < b, d < c, 则这四个变量的排序可能是a < d < c < b;尽管还有其他可能,你只需要找出其中一个即可. 思路: 把每个变量看成一个点,“小于”看成一个边,则得到一个有向图.这样…

Ordering Tasks John has n tasks to do. Unfortunately, the tasks are not independent and the execution of one task isonly possible if other tasks have already been executed.InputThe input will consist of several instances of the problem. Each instance…

2016/5/19 17:39:07 拓扑排序,是对有向无环图(Directed Acylic Graph , DAG )进行的一种操作,这种操作是将DAG中的所有顶点排成一个线性序列,使得图中的任意一对顶点u,v满足如下条件: 若边(u,v)∈E(G),则在最终的线性序列中出现在v的前面 好了,说人话:拓扑排序的应用常常和AOV网相联系,在一个大型的工程中,某些项目不是独立于其他项目的,这意味着这种非独立的项目的完成必须依赖与其它项目的完成而完成,不妨记为u,v,则若边(u,v)∈E(G),代…

拓扑排序模版题型: John has n tasks to do.Unfortunately, the tasks are not independent and the execution of one task is only possible if other tasks have already been executed. Input The input will consist of several instances of the problem. Each instance be…