kmp,根据next数组的性质如果有答案的话就是n/(n-(ne[n]+1)),否则是1 搬来打算用SA后来发现必须用DC3就没写 #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int N=1000005; int n,ne[N]; char s[N]; int main() { while(scanf("%s",s)&&…

Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 36926   Accepted: 15254 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

                                                                                                  Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 38038   Accepted: 15740 Description Given two strings a and b we define a*b t…

Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 30069   Accepted: 12553 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative integer is defin…

Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 37685   Accepted: 15590 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

题目链接:http://poj.org/problem?id=2406 题意:给出一个字符串s,求重复子串出现的最大次数. 分析:kmp的next[]数组的应用. 要求重复子串出现的最大次数,其实就是求字符串的最小循环节. 以下内容转载于:http://bbezxcy.iteye.com/blog/1377787 --------------------------------------------------------------------------------------------…

Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative inte…

http://poj.org/problem?id=2406 只是模板,但是有趣的是一个strcmp的字符串比较函数,学习到了... https://baike.baidu.com/item/strcmp/5495571?fr=aladdin ↑百度的概念 像 poj1961 但是更简单..主要是告诫我要学习一下str相关的函数,似乎说要学str函数好久了也没有经常用过 代码 #include<cstdio> #include<cstring> #include<iostre…

题目链接:http://poj.org/problem?id=2406 题目大意:如果n%(n-next[n])==0,则存在重复连续子串,长度为n-next[n]. 例如:      a    b    a    b    a    b next:-1   0    0    1    2    3    4 next[n]==4,代表着,前缀abab与后缀abab相等的最长长度,这说明,ab这两个字母为一个循环节,长度=n-next[n]; #include <iostream> #inc…