LeetCode(21)题解:Merge Two Sorted Lists】的更多相关文章

https://leetcode.com/problems/merge-two-sorted-lists/ Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 思路: 考察链表操作,没啥说的. AC代码: /** * Definition for singly-lin…
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题目要求: 合并两个有序链表 注意: 不能开辟新的结点空间 解题思路: 1.归并排序,创建一个新的头结点,从头到尾分别遍历两个链表,并依次比较其大小关系,每次将头指针指向小的那个. 2.递归思想(对于为改变链表结构的…
LeetCode第21题 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 翻译: 合并两个有序链表并返回…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:合并,链表,单链表,题解,leetcode, 力扣,Python, C++, Java 题目地址: https://leetcode.com/problems/merge-k-sorted-lists/description/ 题目描述: Merge k sorted linked lists and return it as one sorted li…
# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 23: Merge k Sorted Listshttps://oj.leetcode.com/problems/merge-k-sorted-lists/ Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. ===Comments…
这两天一直也没有顾上记录一下自己做过的题目,回头看看,感觉忘的好快,今天做了一个hard,刚开始觉得挺难得,想了两种方法,一种是每次都从k个list中选取最小的一个,为空的直接跳过,再就是每次合并其中的两个list,直到最终合并完成,这就要用到地柜的方法,还有就是划分,感觉递归的思路比较清晰,就拿地柜的写了,使用递归的方法,这道题目就是以21. Merge Two Sorted Lists  为基础的. 阶梯思路就是,每次都从中间切割lists,直到切割完之后左侧或者右侧为,一个或者两个list…
Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题目意思: 合并K条已经排序的链表.分析时间复杂度. 解题思路: 很容易就想起之前学的合并两条链表的算法,这一题其实就是那个题目的扩展,变成合并K条了.我采用的方法就是迭代法. 如果只有一条,直接返回.如果只有两条,就只需要调用mergeTwo一下.如果超过两…
题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 说明:有序链表归并(从小到大) 1)此链表无头节点 实现: 方法一:非递归 /** * Definition for singly-linked list. * struct ListNode { * int…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 题意:对k个有序的链表进行归并排序.并分析其复杂度. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(N…
题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析 数据结构与算法的链表章节的典型实例,将两个有序链表合成一个,保持其有序的性质. AC代码 /** * Definition for singly-linked list. * struct ListNod…