Python小代码_10_判断是否为素数】的更多相关文章

import math n = int(input('Input an integer:')) m = int(math.sqrt(n) + 1) for i in range(2, m): if n % i == 0: print('No') break else: print('Yes') #输出结果 #Input an integer:23 #Yes…
Python小代码_2_格式化输出 name = input("name:") age = input("age:") job = input("job:") salary = input("salary:") msg = ''' --------- info of %s --------- Name: %s Age: %s Job: %s Salary: %s --------- end --------- ''' % (n…
Python小代码_1_九九乘法表 max_num = 9 row = 1 while row <= max_num: col = 1 while col <= row: print(str(col) + "*" + str(row) + "=" + str(col*row), end="\t") col += 1 row += 1 print()…
import math a = [p for p in range(2, 100) if 0 not in [p % d for d in range(2, int(math.sqrt(p)) + 1)]] print(a) #输出结果 #[2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]…
算法思想 判断某一个数,能不能被比他平方根小的素数整除. 首先看看代码 $arr = [] $arr[0] = 2 def add_prime(n) 3.step(n,2){|num| $arr <<num if is_prime?num } end def is_prime?(number) j=0 while $arr[j]*$arr[j]<=number return false if number % $arr[j] == 0 j += 1 end return true end…
python练手遇到的一个问题写了个统一公式,不用麻烦的分各种类,如果有人测试出错误请评论通知. #分单双月 def dayNum(month,day,isLeap): if month % 2 != 0: if month == 1: days = day else: days = (month - 1) * 30.5 - 2 + (month // 9) + day + isLeap else: if month == 2: days = 31 + day else: days = (mon…
import time date = time.localtime() print(date) #time.struct_time(tm_year=2018, tm_mon=2, tm_mday=24, tm_hour=19, tm_min=42, tm_sec=57, tm_wday=5, tm_yday=55, tm_isdst=0) year = date[0] month = date[1] day = date[2] day_month = [31, 28, 31, 30, 31, 3…
menu = { "北京": { "朝阳区": { "三环到四环之间": {}, "四环到五环之间": {}, "五环到六环之间": {}, "管庄": {}, "北苑": {}, "定福庄": {}, "三环以内": {}, }, "海淀区": { "三环以内": {}, "三…
只能被自己或者1整除的数为质数 num = int(input('请输入一个数:')) if num > 1: # 查看因子 for i in range(2, num): if (num % i) == 0: print(num, "不是质素") print(i, "乘以", num // i, "是", num) break else: print(num, "是质素") # 如果输入的数字小于或等于 1,不是质素…
a = 4 b = 5 #第一种 c = a a = b b = c print(a, b) #输出结果 #5 4 #第二种 a = a + b b = a - b a = a - b print(a, b) #输出结果 #5 4 #第三种 a, b = b, a print(a, b) #输出结果 #5 4…