992. Sort Array By Parity II - LeetCode】的更多相关文章

Question 992. Sort Array By Parity II Solution 题目大意:给一个int数组,一半是奇数一半是偶数,分别对偶数数和奇数数排序并要求这个数本身是偶数要放在偶数位上 思路:把奇数数和偶数数筛选出来后对其分别排序,再按奇偶索引放到原数组上 Java实现: public int[] sortArrayByParityII(int[] A) { List<Integer> oddList = new ArrayList<>(); List<I…
922. Sort Array By Parity II 题目描述 Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may re…
package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: SortArrayByParityII * @Author: xiaof * @Description: 922. Sort Array By Parity II * Given an array A of non-negative integers, half of the…
problem 922. Sort Array By Parity II solution1: class Solution { public: vector<int> sortArrayByParityII(vector<int>& A) { int n = A.size(); , j=; i<n, j<n; ) { ==) i += ; ==) j += ; if(j<n) swap(A[i], A[j]); } return A; } }; 参考 1…
Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that satisfi…
Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that satisfi…
https://leetcode.com/problems/sort-array-by-parity-ii/ Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i]is even, i…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 使用奇偶数组 排序 奇偶数位置变量 日期 题目地址: https://leetcode.com/problems/sort-array-by-parity-ii 题目描述 Given an array A of non-negative integers, half of the integers in A are odd, and half of…
题目要求 Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that sa…
这是悦乐书的第354次更新,第379篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第216题(顺位题号是922).给定非负整数的数组A,A中的一半整数是奇数,而剩下的一半是偶数. 对数组进行排序,以便每当A[i]为奇数时,i就是奇数; A[i]是偶数,i就是偶数. 你可以返回满足此条件的任何答案数组.例如: 输入:[4,2,5,7] 产出:[4,5,2,7] 说明:[4,7,2,5],[2,5,4,7],[2,7,4,5]也将被接受. 注意: 2 <= A.leng…
题目如下: 解题思路:非常简单的题目,引入两个变量oddInx = 1和evenInx = 0,和与A等长的结果数组res.然后遍历A,如果A[i]为偶数,则令res[evenInx] = A[i],evenInx += 2:否则令res[oddInx] = A[i],evenInx += 2. 代码如下: class Solution(object): def sortArrayByParityII(self, A): """ :type A: List[int] :rty…
Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer array that satisfi…
""" Given an array A of non-negative integers, half of the integers in A are odd, and half of the integers are even. Sort the array so that whenever A[i] is odd, i is odd; and whenever A[i] is even, i is even. You may return any answer arra…
Given an array of integers nums, half of the integers in nums are odd, and the other half are even. Sort the array so that whenever nums[i] is odd, i is odd, and whenever nums[i] is even, i is even.  Return any answer array that satisfies this condit…
给定一个非负整数数组 A, A 中一半整数是奇数,一半整数是偶数. 对数组进行排序,以便当 A[i] 为奇数时,i 也是奇数:当 A[i] 为偶数时, i 也是偶数. 你可以返回任何满足上述条件的数组作为答案. 示例: 输入:[4,2,5,7] 输出:[4,5,2,7] 解释:[4,7,2,5],[2,5,4,7],[2,7,4,5] 也会被接受. 提示: 2 <= A.length <= 20000 A.length % 2 == 0 0 <= A[i] <= 1000 clas…
905. Sort Array By Parity Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,…
package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: SortArrayByParity * @Author: xiaof * @Description: 905. Sort Array By Parity * Given an array A of non-negative integers, return an array…
Question 905. Sort Array By Parity Solution 题目大意:数组排序,偶数放前,奇数在后,偶数的数之间不用管顺序,奇数的数之间也不用管顺序 思路:建两个list,一个放偶数,一个放奇数,最后将两个list合并,转化为数组返回 Java实现: public int[] sortArrayByParity(int[] A) { List<Integer> evenList = new ArrayList<>(); List<Integer&g…
problem 905. Sort Array By Parity solution1: class Solution { public: vector<int> sortArrayByParity(vector<int>& A) { vector<int> even, odd; for(auto a:A) { ==) even.push_back(a); else odd.push_back(a); } even.insert(even.end(), odd.…
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] Output: [2,4,3,1] T…
题目如下: 解题思路:本题和[leetcode]75. Sort Colors类似,但是没有要求在输入数组本身修改,所以难度降低了.引入一个新的数组,然后遍历输入数组,如果数组元素是是偶数,插入到新数组头部,否则追加到尾部. 代码如下: class Solution(object): def sortArrayByParity(self, A): """ :type A: List[int] :rtype: List[int] """ res =…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述: 题目大意 解题方法 自定义sorted函数的cmp 日期 题目地址:https://leetcode.com/problems/sort-array-by-parity/description/ 题目描述: Given an array A of non-negative integers, return an array consisting of all the…
题目要求 Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. 题目分析及思路 题目给出一个含有非负整数的数组A,要求返回一个数组,前面的元素都是A…
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] Output: [2,4,3,1] T…
这是悦乐书的第347次更新,第371篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第212题(顺位题号是905).给定一个非负整数数组A,返回一个由A的所有偶数元素组成的数组,后跟A的所有奇数元素. 你可以返回满足此条件的任何答案数组.例如: 输入:[3,1,2,4] 输出:[2,4,3,1] 说明:[4,2,3,1],[2,4,1,3]和[4,2,1,3]也是正确答案. 注意: 1 <= A.length <= 5000 0 <= A[i] <= 5…
题目 Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] Output: [2,4,3,1…
原题链接 很水的一道题,就是数组内部交换. 水题就想着减少复杂度嘛,于是学到一种交换写法. class Solution { public: vector<int> sortArrayByParity(vector<int> &A) { int i = 0, j = A.size()-1; while (i < j) { if (A[i] & 0x01) { A[i] ^= A[j]; A[j] ^= A[i]; A[i] ^= A[j]; --j; } el…
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] Output: [2,4,3,1] T…
Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1: Input: [3,1,2,4] Output: [2,4,3,1] T…
Description Given an array A of non-negative integers, return an array consisting of all the even elements of A, followed by all the odd elements of A. You may return any answer array that satisfies this condition. Example 1 Input: [3,1,2,4] Output:…