How Many Paths Are There Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1010    Accepted Submission(s): 332 Problem Description   oooccc1 is a Software Engineer who has to ride to the work plac…

http://acm.hdu.edu.cn/showproblem.php?pid=3191 这道题求次短路经和路径数 #include <cstdio> #include <cstring> #include <vector> #include <queue> #include <algorithm> #define maxn 2000 using namespace std; <<; struct edge { int v,w;…

Sightseeing Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1023    Accepted Submission(s): 444 Problem Description Tour operator Your Personal Holiday organises guided bus trips across the Ben…

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in th…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1688 题目大意:给n个点,m条有向边.再给出起点s, 终点t.求出s到t的最短路条数+次短路条数. 思路: 1.最短路和次短路是紧密相连的,在最短路松弛操作中,当我们找到一条更短的路径,也就意味着之前的路径不再是最短路,而成为了次短路,利用这个关系可以实现状态的转移. 2.好久没写优先队列了,都忘记了加个 priority_queue, 这样才能写重载,才能排序. 注释在代码里: #include<…

http://acm.hdu.edu.cn/showproblem.php?pid=3191 求次短路的长度和个数 相关分析在这里http://blog.csdn.net/u012774187/article/details/40681515 #pragma comment(linker, "/STACK:36777216") #pragma GCC optimize ("O2") #include <cstdio> #include <cstdl…

Two Paths Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 153428/153428 K (Java/Others) Total Submission(s): 2184 Accepted Submission(s): 856 Problem Description You are given a undirected graph with n nodes (numbered from 1 to n) and m edges. A…

[链接]http://acm.hdu.edu.cn/showproblem.php?pid=6181 [题意] 让你求从1到n的次短路 [题解] 模板题; 因为点可以重复走; 则一定会有次短路. dijkstra算法+优先队列优化一下就好. [错的次数] 11+ [反思] 在写优先队列的时候,节点和路径长度写反了..应该节点写在后面才行的.. [代码] #include <bits/stdc++.h> using namespace std; #define lson l,m,rt<&l…

http://www.cnblogs.com/wally/archive/2013/04/16/3024490.html http://blog.csdn.net/me4546/article/details/6584448 维护最短路长度d[i][0]和次短路d[i][1],最短路条数dp[i][0]和次短路dp[i][1] #include <iostream> #include <string> #include <cstring> #include <cs…

题目链接 题意 给出n个点m条边的无向图,求次短路. 思路 和 POJ 2449 类似,只不过大小要开成long long. #include <bits/stdc++.h> using namespace std; typedef long long LL; const int N = 100011; const int INF = 0x3f; struct Edge { int v, nxt; LL w; } edge[N*2]; struct Node { int u; LL g, h;…