Language: Default Long Long Message Time Limit: 4000MS Memory Limit: 131072K Total Submissions: 21228 Accepted: 8708 Case Time Limit: 1000MS Description The little cat is majoring in physics in the capital of Byterland. A piece of sad news comes…
算法见:http://www.cnblogs.com/grenet/archive/2010/06/03/1750454.html 求最长公共子串(不需要连续) #include <stdio.h> #include <string> #define N 100 int max(int a, int b, int c){ return (a>b?a:b)>c?(a>b?a:b):c; } int needleman(char s1[], char s2[]){ i…
反恐训练营 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3040 Accepted Submission(s): 693 Problem Description 当今国际反恐形势非常严峻,特别是美国"9.11事件"以后,国际恐怖势力更是有恃无恐,制造了多起骇人听闻的恐怖事件.基于此,各国都十分操心恐怖势力会对本国社会…
POJ 3080 Blue Jeans (求最长公共字符串) Description The Genographic Project is a research partnership between IBM and The National Geographic Society that is analyzing DNA from hundreds of thousands of contributors to map how the Earth was populated. As an IB…
传送门 Description Alex has two sequences a1,a2,...,an and b1,b2,...,bm. He wants find a longest common subsequence that consists of consecutive values in increasing order. Input There are multiple test cases. The first line of input contains an integer…
Justice String Given two strings A and B, your task is to find a substring of A called justice string, which has the same length as B, and only has at most two characters different from B. Input The first line of the input contains a single integer…
Common Subsequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 45763 Accepted: 18737 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..…
1这道题目就是给定两个字符串,然后求这两个字符串的最长公共子串的最大长度,假设我的f()方法是来求两个字符串的最大公共子串,从头开始逐一比较,如果相等,则 继续调用这个方法,使得递归的长度+1,如果不相等,则只要比较s1截掉一个和s2比较,和s2截掉和s1比较,两个中的最大者,如果s1或者s2中有一个长度为0,则最大公共长度就是0,return 2.代码示例: package zzl; public class 最长公共子串 { public static void main(String[]…
摘要:本文讨论了最长公共子串的的相关算法的时间复杂度,然后在后缀数组的基础上提出了一个时间复杂度为o(n^2*logn),空间复杂度为o(n)的算法.该算法虽然不及动态规划和后缀树算法的复杂度低,但其重要的优势在于可以编码简单,代码易于理解,适合快速实现. 首先,来说明一下,LCS通常指的是公共最长子序列(Longest Common Subsequence,名称来源参见<算法导论>原书第3版p223),而不是公共最长子串(也称为最长公共子串). 最长公共子串问题是在文本串.模式串中寻找共有的…
题目描述: Find a longest common subsequence of two strings. 输入: First and second line of each input case contain two strings of lowercase character a…z. There are no spaces before, inside or after the strings. Lengths of strings do not exceed 100. 输出: Fo…
这道题是LIS(最长上升子序列)与LCS(最长公共子序列)问题的综合版本,有关这两个问题可以看一下我的文章:https://www.cnblogs.com/myhnb/p/11305551.html 把这两个问题的解法结合,不难想到以下方法 C++代码 #include<bits/stdc++.h> using namespace std; ; int a[N],b[N]; int f[N][N]; int n; int main(){ cin>>n; ;i<=n;i++)…
