来自http://www.geeksforgeeks.org/dynamic-programming-set-7-coin-change/ 对于整数N,找出N的所有零钱的表示.零钱可以用S={s1,s2,s3,..sm}表示,每种零钱的数量为无穷.请问有多少种找零的方法? 例如, N = 4,S = {1,2,3},有四种找零方式{1,1,1,1},{1,1,2},{2,2},{1,3},return 4 N = 10,S= {2,5,3,6} ,有5中找零方式{2,2,2,2,2}, {2,2…

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins,…

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins,…

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin. Note: You can assume that…

也是常见套路. # coding = utf-8 def rec_mc(coin_value_list, change, know_results): min_coins = change if change in coin_value_list: know_results[change] = 1 return 1 elif know_results[change] > 0: return know_results[change] else: for i in [c for c in coin_…

1. array_chunk 实现 http://php.net/manual/en/function.array-chunk.php <?php function my_array_chunk($a, $sz) { $b = []; if ($sz < 1) { throw new Exception("size is less than 1"); return null; } for ($i = 0, $n = count($a); $i < $n; $i++)…

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin. Note: You can assume that…

You are given coins of different denominations and a total amount of money. Write a function to compute the number of combinations that make up that amount. You may assume that you have infinite number of each kind of coin. Note: You can assume that…

Ref: [Optimization] Dynamic programming[寻找子问题] Ref: [Optimization] Advanced Dynamic programming[优于recursion] 显然,本篇是关于”动态规划"的部分. 找零钱 一.简单直白策略 要点:”个数“其实代表了“for循环”的层数.但“个数”不定,使用“递归”反而能解决这个问题,减少思路上的负担. import time def recMC(coinValueList, change): minCoi…

JSU省赛队员选拔赛个人赛1 一.题目概述: A.Coin Change(暴力求解.动态规划)     B.Fibbonacci Number(递推求解) C.Max Num(排序.比较) D.单词数(字符串比较.库函数运用) E.无限的路(平面几何) F.叠筐(规律输出) 二.解题报告: A.Coin Change 给一个钱的总金额,求出用100个以内的50分.25分.10分.5分.1分硬币拼成该金额的不同拼法. 直接暴力,打表什么的都是浮云.开始总觉得用暴力求解显得自己没风度,不够高端霸气上…