hdu 1690(Floyed)】的更多相关文章

Bus System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8055    Accepted Submission(s): 2121 Problem Description Because of the huge population of China, public transportation is very importa…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1690 Bus System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6569    Accepted Submission(s): 1692 Problem Description Because of the huge popula…
WA了好多次... 这题要用long long 而且INF要设大一点 Sample Input2 //T1 2 3 4 1 3 5 7 //L1-L4 C1-C4 距离和花费4 2 //结点数 询问次数1 //结点的横坐标2341 4 //起点 终点4 11 2 3 4 1 3 5 74 1123101 4 Sample OutputCase 1:The minimum cost between station 1 and station 4 is 3.The minimum cost betw…
Arbitrage Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6522    Accepted Submission(s): 3019 Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform o…
Minimum Transport Cost Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9814    Accepted Submission(s): 2641 Problem Description These are N cities in Spring country. Between each pair of cities…
变形课 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 20748    Accepted Submission(s): 7494 Problem Description 呃......变形课上Harry碰到了一点小麻烦,因为他并不像Hermione那样能够记住所有的咒语而随意的将一个棒球变成刺猬什么的,但是他发现了变形咒语的一个统一规…
题目大意:给出若干巴士不同价格的票的乘坐距离范围,现在有N个站点,有M次询问,查询任意两个站点的最小花费 解析:由于是多次查询不同站点的最小花费,所以用弗洛伊德求解 时间复杂度(O^3) 比较基础的弗洛伊德 #include <iostream> #include <cstdio> #include <cstring> using namespace std; #define INF 1000000000000 typedef __int64 LL; ; __int64…
题意:给你n个数,这些数可以互相加或者减,输出在范围[1,sum]里不能通过运算得出的数 思路:套母函数模版 #include <iostream> #include<cstdio> using namespace std; #define N 110 int a[N],c1[10010],c2[10010],v[10010]; int main(int argc, char** argv) { int n,sum,i,j,k,ans; while(scanf("%d&q…
Problem Description Because of the huge population of China, public transportation is very important. Bus is an important transportation method in traditional public transportation system. And it's still playing an important role even now. The bus sy…
Bus System Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6082    Accepted Submission(s): 1560 Problem Description Because of the huge population of China, public transportation is very importa…