826. Most Profit Assigning Work】的更多相关文章

https://leetcode.com/problems/most-profit-assigning-work/description/ class Solution { public: int maxProfitAssignment(vector<int>& difficulty, vector<int>& profit, vector<int>& worker) { ; vector<pair<int,int>> j…
原题链接在这里:https://leetcode.com/problems/most-profit-assigning-work/ 题目: We have jobs: difficulty[i] is the difficulty of the ith job, and profit[i] is the profit of the ith job. Now we have some workers. worker[i] is the ability of the ith worker, whic…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/most-profit-assigning-work/description/ 题目描述: We have jobs: difficulty[i] is the difficulty of the ith job, and profit[i] is the profit of the ith job. Now we…
We have jobs: difficulty[i] is the difficulty of the ith job, and profit[i] is the profit of the ith job. Now we have some workers. worker[i] is the ability of the ith worker, which means that this worker can only complete a job with difficulty at mo…
We have jobs: difficulty[i] is the difficulty of the ith job, and profit[i] is the profit of the ith job. Now we have some workers. worker[i] is the ability of the ith worker, which means that this worker can only complete a job with difficulty at mo…
双指针基础 双指针(Two Pointers)是面对数组.链表结构的一种处理技巧.这里“指针”是泛指,不但包括通常意义上的指针,还包括索引.迭代器等可用于遍历的游标. 同方向指针 设定两个指针.从头往尾(或从尾到头)遍历,我称之为同方向指针,第一个指针用于遍历,第二个指针满足一定条件下移动.例如 LeetCode题目 283. Move Zeroes: // 283. Move Zeroes void moveZeroes(vector<int>& nums) { ; ;j<nu…
All LeetCode Questions List(Part of Answers, still updating) 题目汇总及部分答案(持续更新中) Leetcode problems classified by company 题目按公司分类(Last updated: October 2, 2017) .   Top Interview Questions # Title Difficulty Acceptance 1 Two Sum Medium 17.70% 2 Add Two N…
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…
[3]Longest Substring Without Repeating Characters [11]Container With Most Water [15]3Sum (2019年2月26日) 给了一个乱序的数组,返回一个结果数组,数组里面每个元素是一个三元组, 三元组的和加起来为0. 题解:先固定第一个数,然后后面两个数的控制用夹逼定理,2 pointers 来解. class Solution { public: vector<vector<int>> threeSu…
Contest 81 (2018年11月8日,周四,凌晨) 链接:https://leetcode.com/contest/weekly-contest-81 比赛情况记录:结果:3/4, ranking: 440/2797.这次题目似乎比较简单,因为我比赛的时候前三题全做出来了(1:12:39),然后第四题有思路,正在写,没写完,比赛完了写完提交也对了. [821]Shortest Distance to a Character(第一题 4分) 给了一个单词(字符串)s,和单词中的任意一个字母…