POJ 1860 Currency Exchange （最短路）

【POJ 1860 Currency Exchange （最短路）】的更多相关文章

POJ 1860 Currency Exchange 最短路+负环

原题链接:http://poj.org/problem?id=1860 Currency Exchange Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 23055 Accepted: 8328 Description Several currency exchange points are working in our city. Let us suppose that each point specializes…

POJ 1860 Currency Exchange (最短路)

Currency Exchange Time Limit:1000MS Memory Limit:30000KB 64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1860 Appoint description: System Crawler (2015-05-14) Description Several currency exchange points are working in our city. Le…

poj 1860 Currency Exchange (最短路bellman_ford思想找正权环最长路)

感觉最短路好神奇呀,刚开始我都没想到用最短路题目:http://poj.org/problem?id=1860 题意:有多种从a到b的汇率,在你汇钱的过程中还需要支付手续费,那么你所得的钱是 money=(nowmoney-手续费)*rate,现在问你有v钱,从s开始出发交换钱能不能赚钱题解:这题其实是用bellman_ford的思想,通过n-1次松弛后,如果还能增加,就说明有环可以使金钱数不断增加. #include <iostream> #include<cstdio>…

POJ 1860 Currency Exchange 最短路难度:0

http://poj.org/problem?id=1860 #include <cstdio> //#include <queue> //#include <deque> #include <cstring> using namespace std; #define MAXM 202 #define MAXN 101 int n,m; int first[MAXN]; int next[MAXM]; int pto[MAXM]; double earn[M…

最短路(Bellman_Ford) POJ 1860 Currency Exchange

题目传送门 /* 最短路(Bellman_Ford):求负环的思路,但是反过来用,即找正环详细解释:http://blog.csdn.net/lyy289065406/article/details/6645778 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <vector> #include <cmat…

POJ 1860 Currency Exchange / ZOJ 1544 Currency Exchange （最短路径相关，spfa求环）

POJ 1860 Currency Exchange / ZOJ 1544 Currency Exchange (最短路径相关,spfa求环) Description Several currency exchange points are working in our city. Let us suppose that each point specializes in two particular currencies and performs exchange operations onl…