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<Random>382 380

382. Linked List Random Node class Solution { ListNode node; Random random; /** @param head The linked list's head. Note that the head is guaranteed to be not null, so it contains at least one node. */ public Solution(ListNode head) { node = head; ra…

LeetCode分类-前400题

1. Array 基础 27 Remove Element 26 Remove Duplicates from Sorted Array 80 Remove Duplicates from Sorted Array II 277 Find the Celebrity 189 Rotate Array 41 First Missing Positive 299 Bulls and Cows 134 Gas Station 118 Pascal's Triangle 很少考 119 Pascal's…

echarts demo

<!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>Visualization</title> <meta name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no&quo…

<Random> 380 381（hard） 138

380. Insert Delete GetRandom O(1) class RandomizedSet { ArrayList<Integer> nums; HashMap<Integer, Integer> locs; Random rand = new Random(); /** Initialize your data structure here. */ public RandomizedSet() { nums = new ArrayList<Integer&g…

[LeetCode] 382. Linked List Random Node 链表随机节点

Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen. Follow up: What if the linked list is extremely large and its length is unknown to you? Could you solve this effi…

Leetcode 382. Linked List Random Node

本题可以用reservoir sampling来解决不明list长度的情况下平均概率选择元素的问题. 假设在[x_1,...,x_n]只选一个元素,要求每个元素被选中的概率都是1/n,但是n未知. 其中 random.randint(0, cnt) == 0: 的概率是1/(cnt+1).reservoir sampling的证明可以使用归纳法(induction). class Solution(object): def __init__(self, head): """…

382. Linked List Random Node

Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen. Follow up:What if the linked list is extremely large and its length is unknown to you? Could you solve this effic…

[LeetCode] 382. Linked List Random Node ☆☆☆

Given a singly linked list, return a random node's value from the linked list. Each node must have the same probability of being chosen. Follow up: What if the linked list is extremely large and its length is unknown to you? Could you solve this effi…

382. Linked List Random Node（蓄水池采样）

1. 问题 给定一个单链表,随机返回一个结点,要求每个结点被选中的概率相等. 2. 思路 在一个给定长度的数组中等概率抽取一个数,可以简单用随机函数random.randint(0, n-1)得到索引来抽取. 本题是给定了链表,当然也好做,可以事先遍历一次求长度,每次要取的时候随机求索引,然后遍历一次. 时间复杂度O(n),空间复杂度O(1) 或者事先把数据放到数组中,每次要取的时候随机求索引,然后直接取到对应的数. 时间复杂度O(1),空间复杂度O(n) (延伸一下)如果对于长度未知,会不断增…

382 Linked List Random Node 链表随机节点

给定一个单链表,随机选择链表的一个节点,并返回相应的节点值.保证每个节点被选的概率一样.进阶:如果链表十分大且长度未知,如何解决这个问题?你能否使用常数级空间复杂度实现?示例:// 初始化一个单链表 [1,2,3].ListNode head = new ListNode(1);head.next = new ListNode(2);head.next.next = new ListNode(3);Solution solution = new Solution(head);// getRand…