P1825 [USACO11OPEN]玉米田迷宫Corn Maze 题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in…

P1825 [USACO11OPEN]玉米田迷宫Corn Maze 题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in…

https://www.luogu.org/problem/show?pid=1825 题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from on…

题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in the maze to another. The slides w…

题目链接:https://www.luogu.org/problemnew/show/P1825 带有传送门的迷宫问题 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; const int maxn = 2001; char map[maxn][maxn]; int fx[4] = {0, 1, 0, -1};…

题目描述 This past fall, Farmer John took the cows to visit a corn maze. But this wasn't just any corn maze: it featured several gravity-powered teleporter slides, which cause cows to teleport instantly from one point in the maze to another. The slides w…

P1825 传送门 简单的题意 就是一个有传送门的迷宫问题(我一开始以为是只有1个传送门,然后我就凉了). 大体思路 先把传送门先存起来,然后跑一下\(BFS\). 然后,就做完了. 代码鸭 #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> #include <iomanip> #include…

洛谷P1879 [USACO06NOV]玉米田Corn Fields \(f[i][j]\) 表示前 \(i\) 行且第 \(i\) 行状态为 \(j\) 的方案总数.\(j\) 的大小为 \(0 \to (1 >> n - 1)\) . 第 \(i\) 行,种植状态为 \(j\) 的方案总数等于所有合法的 \(f[i-1][k]\) 之和. 状态 \(j\) 满足同一行内没有相邻的两块草地(没有共同边). 状态 \(j\) 和 \(k\) 满足相邻两行的种植情况没有两块草地有共同边. \[…

玉米田Corn Fields 题目链接 此题和互不侵犯状压DP的做法类似 f[i][j]表示前i行,第i行种植(1)/不种植(0)构成的二进制数为j时的方案数 首先我们可以预处理出所有一行中没有两个相邻的1的二进制数 然后进行暴力的DP #include<cstdio> #define mod 100000000 #define N 13 #define M 4100 int n,m,f[N][M],a[N]; ],cnt,ans; inline int read(){ char c=getc…

没学状压DP的看一下 合法布阵问题  P1879 [USACO06NOV]玉米田Corn Fields 题意:给出一个n行m列的草地(n,m<=12),1表示肥沃,0表示贫瘠,现在要把一些牛放在肥沃的草地上,但是要求所有牛不能相邻,问你有多少种放法. 分析:假如我们知道每行都有x种合法放法(也就是x种状态),所以对于第i行就有x种放法,那么对于第i+1行的每种放法就有对应的x种放法. 所以定义dp[i][j]表示第i行状态为j时的方法数(j=0,j<=x;j++),有转移方程:dp[i][j]…