Gold Transportation Time Limit: 2000ms Memory Limit: 65536KB This problem will be judged on PKU. Original ID: 322864-bit integer IO format: %lld      Java class name: Main   Recently, a number of gold mines have been discovered in Zorroming State. To…

参考链接:http://www.cnblogs.com/jiaohuang/archive/2010/11/13/1876418.html 题意:地图上某些点有金子,有些点有房子,还有一些带权路径,问把所有金子运到房子里所要经过最小的最大相邻路是多少. 也就是如果光用比“最小的最大相邻路”那条路更小的路是无法运完所有金子的,那么可以先对路径排序,然后一条一条取, 看看是否满足条件:即是否所有并查集的根节点的权值f[i]为非负. 思路:首先想到的是,要能运完所有的金子,那么必须任意一个连通器中的储…

题目链接 给出n个城市, 每个城市有一个仓库, 仓库有容量限制, 同时每个城市也有一些货物, 货物必须放到仓库中. 城市之间有路相连, 每条路有长度. 因为有些城市的货物量大于仓库的容量, 所以要运到别的城市,求所有货物都放到仓库中时, 走过的路中, 最长的那条路最短的情况, 输出这条路的长度. 很容易想到二分, 如果城市之间路的长度小于二分值x, 那么两个城市之间连边, 权值为inf. 源点和所有城市连边, 权值为一开始的货物量, 每个城市和这个城市的仓库连边, 权值inf, 每个仓库和汇点连…

poj 1797 Heavy Transportation Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a way from the place his customer has…

POJ 1797 Heavy Transportation / SCU 1819 Heavy Transportation (图论,最短路径) Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there reall…

POJ.1797 Heavy Transportation (Dijkstra变形) 题意分析 给出n个点,m条边的城市网络,其中 x y d 代表由x到y(或由y到x)的公路所能承受的最大重量为d,求从1到n的所有通路中,所能经过的的最大重量的车为多少. 2. 代码总览 #include <cstdio> #include <cstring> #include <algorithm> #include <queue> #include <stack&…

Gold Transportation Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 3079 Accepted: 1101 Description Recently, a number of gold mines have been discovered in Zorroming State. To protect this treasure, we must transport this gold to the stor…

题目链接:http://poj.org/problem?id=3228 思路:增设一个超级源点和一个超级汇点,源点与每一个gold相连,容量为gold数量,汇点与仓库相连,容量为仓库的容量,然后就是二分最小的最大相邻距离,跑最大流验证即可.最大流用的是别人的Dinic模版. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<queue&g…

F - Heavy Transportation Time Limit:3000MS     Memory Limit:30000KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1797 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand busines…

题目链接:http://poj.org/problem?id=1797 Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 30840   Accepted: 8191 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand…

1.链接地址: http://bailian.openjudge.cn/practice/2000 http://poj.org/problem?id=2000 2.题目: 总Time Limit: 1000ms Memory Limit: 65536kB Description The king pays his loyal knight in gold coins. On the first day of his service, the knight receives one gold c…

题目链接:[http://poj.org/problem?id=3228] 题意:给出n个村庄,每个村庄有金矿和仓库,然后给出m条边连接着这个村子.问题是把所有的金矿都移动到仓库里所要经过的路径的最大值的最小值. 题解:贪心,把边排序,然后从小到大加边,如果加到某一条边之后,金矿都可以移动到仓库了,那么这条边就是结果.首先明白,如果一些边连接的一些村庄的仓库的总容量大于总金矿数,那么这些村庄的金矿就可以全部移动到仓库里了.如果在从小到大加边的时候形成了环,那么这条边可以不要(加进去也不会影响结果…

Heavy Transportation Time Limit:3000MS     Memory Limit:30000KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1797 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. B…

原题链接:http://poj.org/problem?id=1797 Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 24576   Accepted: 6510 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand…

传送门 Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 31882   Accepted: 8445 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever…

Gold Balanced Lineup Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10924 Accepted: 3244 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by h…

Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 26968   Accepted: 7232 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man…

http://poj.org/problem?id=1797 给定n个点,及m条边的最大负载,求顶点1到顶点n的最大载重量. 用Dijkstra算法解之,只是需要把“最短路”的定义稍微改变一下, A到B的路长定义为路径上边权最小的那条边的长度, 而最短路其实是A到B所有路长的最大值. #include<stdio.h> #include<string.h> #include<math.h> #include<stdlib.h> #include<alg…

Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 22440   Accepted: 5950 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man…

题目 改动见下,请自行画图理解 具体细节也请看下面的代码: 这个花了300多ms #define _CRT_SECURE_NO_WARNINGS #include<string.h> #include<stdio.h> #include<math.h> #include<algorithm> using namespace std; ; #define typec int ;//防止后面溢出,这个不能太大 bool vis[MAXN]; typec cost…

Heavy Transportation 题目链接: http://acm.hust.edu.cn/vjudge/contest/66569#problem/A Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether th…

http://poj.org/problem?id=1797 题意 :给出N个城市M条边,每条边都有容量值,求一条运输路线使城市1到N的运输量最大. 思路 :用dijkstra对松弛条件进行变形.解释一下样例吧:从1运到3有两种方案方案1:1-2-3,其中1-2承重为3,2-3承重为5,则可以运送货物的最大重量是3(当大于3时明显1到不了2)方案2:1-3,可知1-3承重为4,故此路可运送货物的最大重量是4,故答案输出4 #include <iostream> #include <std…

题目:http://poj.org/problem?id=3274 #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack> #include<queue> #include<iomanip> #include<cmath> #include<map> #include<ve…

http://poj.org/problem?id=3274 题意 :农夫约翰的n(1 <= N <= 100000)头奶牛,有很多相同之处,约翰已经将每一头奶牛的不同之处,归纳成了K种特性,比如1号特性代表它身上有斑点,2号特性代表它比较喜欢用passcal 写程序而不是C .约翰使用“特性标识符”来描述奶牛的各种特性,例如:一头奶牛的特性标识符是13,将13写成二进制1101,从右向左看,就表示这头奶牛具有1,3,4这三个特性,但没有2号特性,约翰把n头奶牛排成一排,发现在有些连续区间里的…

题目链接: http://poj.org/problem?id=1797 Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a way from the place his customer has buil…

Heavy Transportation Time Limit: 3000MS   Memory Limit: 30000K Total Submissions:46898   Accepted: 12204 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man…

题目链接:http://poj.org/problem?id=2000 题目大意:求N天得到多少个金币,第一天得到1个,第二.三天得到2个,第四.五.六天得到3个....以此类推,得到第N天的金币数. #include <iostream> #include <cstdio> #include <cmath> using namespace std; int main () { int x,n,p; while(cin>>n) { ) break; x=p=…

一.Description The king pays his loyal knight in gold coins. On the first day of his service, the knight receives one gold coin. On each of the next two days (the second and third days of service), the knight receives two gold coins. On each of the ne…

题目链接:POJ 1797 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a way from the place his customer has build his giant…

题目链接:POJ 1797 Description Background Hugo Heavy is happy. After the breakdown of the Cargolifter project he can now expand business. But he needs a clever man who tells him whether there really is a way from the place his customer has build his giant…