1118 Birds in Forest (25 分) Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in…

Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pai…

此文章 同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/89819984   1118 Birds in Forest (25 分)   Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree…

1118 Birds in Forest (25 分) Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in…

1118. Birds in Forest (25) Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in…

并查集合并 #include<iostream> using namespace std; const int MAX = 10010; int father[MAX],root[MAX]; int findfather(int x){ if(x==father[x]) return x; else{ int F=findfather(father[x]); father[x]=F; return F; } } void Union(int a , int b){ int faA=findfa…

如题... #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> using namespace std; /* 并查集水题 */ +; struct UF{ int father[maxn]; void init(){ ;i<maxn;i++) father[i]=i; } int find_root(int x){ if(father[x]!=x…

题意: 输入一个正整数N(<=10000),接着输入N行数字每行包括一个正整数K和K个正整数,表示这K只鸟是同一棵树上的.输出最多可能有几棵树以及一共有多少只鸟.接着输入一个正整数Q,接着输入Q行每行包括两个正整数,输出它们是否在同一棵树上. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]; int find_(int x){ if(x==f…

Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pai…

Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pai…

Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pai…

题意: 思路:并查集模板题. 代码: #include <cstdio> #include <algorithm> using namespace std; ; int father[maxn]; }; void Init() { ;i<maxn;i++) father[i]=i; } int FindSet(int a) { int root=a; while(father[root]!=root) root=father[root]; //剪枝,(不剪枝会超时哦) whi…

1118. Birds in Forest (25) 时间限制 150 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supp…

Source: PAT A1118 Birds in Forest (25 分) Description: Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the…

Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pai…

Some scientists took pictures of thousands of birds in a forest. Assume that all the birds appear in the same picture belong to the same tree. You are supposed to help the scientists to count the maximum number of trees in the forest, and for any pai…

思路:并查集一套带走. AC代码 #include <stdio.h> #include <string.h> #include <algorithm> using namespace std; const int maxn = 10000+5; int par[maxn], vis[maxn]; int findRoot(int x) { return x == par[x] ? x : par[x] = findRoot(par[x]); } void unionS…

1001. A+B Format (20) 注意负数,没别的了. 用scanf来补 前导0 和 前导的空格 很方便. #include <iostream> #include <cstdio> using namespace std; ]; int main() { int A,B; cin>>A>>B; A+=B; ) { A=-A; cout<<"-"; } ; while(A) { a[n++]=A%; A/=; } ;…

2019/4/3 1063 Set Similarity n个序列分别先放进集合里去重.在询问的时候,遍历A集合中每个数,判断下该数在B集合中是否存在,统计存在个数(分子),分母就是两个集合大小减去分子. // 1063 Set Similarity #include <set> #include <map> #include <cstdio> #include <iostream> #include <algorithm> using name…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

最短路径 Emergency (25)-PAT甲级真题(Dijkstra算法) Public Bike Management (30)-PAT甲级真题(Dijkstra + DFS) Travel Plan (30)-PAT甲级真题(Dijkstra + DFS,输出路径,边权) All Roads Lead to Rome (30)-PAT甲级真题-Dijkstra + DFS Online Map (30)-PAT甲级真题(Dijkstra + DFS) 最短路径扩展问题 要求数最短路径有多…

1.并查集的定义 在计算机科学中,并查集是一种树型的数据结构,用于处理一些不交集(Disjoint Sets)的合并及查询问题.有一个联合-查找算法(union-find algorithm)定义了两个用于此数据结构的操作: Find:确定元素属于哪一个子集. Union:将两个子集合并成同一个集合. MakeSet,用于建立单元素集合. 为了更加精确的定义这些方法,需要定义如何表示集合.一种常用的策略是为每个集合选定一个固定的元素,称为代表,以表示整个集合.接着,Find(x) 返回x所属集合…

并查集 PAT (Advanced Level) Practice 并查集 相关题 <算法笔记> 重点摘要 1034 Head of a Gang (30) 1107 Social Clusters (30) 1118 Birds in Forest (25) <算法笔记> 9.6 并查集 重点摘要 1. 定义 father[i] 表示元素 i的父结点 father[i] = i 表示元素 i 为该集合根结点 每个集合只存在一个根结点,且其作为所属集合的标识 int father[…

Source: PAT (Advanced Level) Practice Reference: [1]胡凡,曾磊.算法笔记[M].机械工业出版社.2016.7 Outline: 基础数据结构: 线性表:栈,队列,链表,顺序表 树:二叉树的建立,二叉树的遍历,完全二叉树,二叉查找树,平衡二叉树,堆,哈夫曼树 图:图的存储和遍历 经典高级算法: 深度优先搜索,广度优点搜索,回溯剪枝 贪心,并查集,哈希映射 最短路径(只考察过单源),拓扑排序(18年9月第一次涉及相关概念,未正式考过),关键路径(未…

专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…

PoPo数据可视化 聚焦于Web数据可视化与可视化交互领域,发现可视化领域有意思的内容.不想错过可视化领域的精彩内容, 就快快关注我们吧 :) 微信号:popodv_com   由于国庆节的原因,累计了2期可视化视频,一并在本期放出,视频就放在文章最顶部吧. 视频1. 鸟的迁徙 Nightflights, bird migration - visualising gps tracks for ZDF series with Colourfield TV.   视频2和3. 城市中狗的时空轨迹可视…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4603    Accepted Submission(s): 1671 Problem DescriptionJimmy experiences a lot of stress at work these days, especially…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5679    Accepted Submission(s): 2086 Problem Description Jimmy experiences a lot of stress at work these days, especiall…

A Walk Through the Forest Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4383    Accepted Submission(s): 1573 Problem Description Jimmy experiences a lot of stress at work these days, especiall…