Necklace of Beads Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 630 Accepted Submission(s): 232 Problem Description Beads of red, blue or green colors are connected together into a circular…
非常裸的polya,只是我看polya看了非常久 吉大ACM模板里面也有 #include <cstdio> #include <cmath> #include <iostream> using namespace std; long long gcd(long long a,long long b) { return b==0?a:gcd(b,a%b); } int main() { #ifndef ONLINE_JUDGE //freopen("G:/1.…
Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 9359 Accepted: 3862 Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 24 ). If the repetitions that are produced by rotation…
Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 24 ). If the repetitions that are produced by rotation around the center of the circular necklace or reflection to the axis of symmetry ar…
Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 24 ). If the repetitions that are produced by rotation around the center of the circular necklace or reflection to the axis of symmetry are all neglec…
Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 8263 Accepted: 3452 Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 24 ). If the repetitions that are produced by rotation…
和poj 2409差不多,就是k变成3了,详见 还有不一样的地方是记得特判n==0的情况不然会RE #include<iostream> #include<cstdio> using namespace std; long long n,ans; long long ksm(long long a,long long b) { long long r=1; while(b) { if(b&1) r=r*a; a=a*a; b>>=1; } return r; }…
Necklace of Beads Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 7451 Accepted: 3102 Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 24 ). If the repetitions that are pro…
Necklace of Beads Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1049 Accepted Submission(s): 378 Problem Description Beads of red, blue or green colors are connected together into a circula…
Necklace of Beads Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1817 Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 40 ). If…
Necklace of Beads Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 7874 Accepted: 3290 Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 24 ). If the repetitions that are pro…
Necklace of Beads Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 7763 Accepted: 3247 Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < 24 ). If the repetitions that are pro…
Description Beads of red, blue or green colors are connected together into a circular necklace of n beads ( n < ). If the repetitions that are produced by rotation around the center of the circular necklace or reflection to the axis of symmetry are…
http://poj.org/problem?id=1286 题意:求用3种颜色给n个珠子涂色的方案数.polya定理模板题. #include <stdio.h> #include <math.h> long long gcd(long long a,long long b) { return b?gcd(b,a%b):a; } int main() { long long n; while(~scanf("%lld",&n)) { ) break;…
Let it Bead Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 5365 Accepted: 3585 Description "Let it Bead" company is located upstairs at 700 Cannery Row in Monterey, CA. As you can deduce from the company name, their business is b…
POJ 2409 Let it Bead 这题就是polya公式的直接套用,唯一麻烦的是置换群的种类数,由于可以翻转,所以除了要加上pow(c,gcd(s,i))这些平面旋转的置换群,还要加上翻转的.由于翻转的情况奇偶是不同的,所以需要分开讨论:偶数:pow(c,(s-2)/2+2)*(s/2)+pow(c,(s/2))*(s/2);(里面包含了两个对点和两个对边的旋转) 奇数:pow(c,(s-1)/2+1)*s;(一个点和对边的旋转) #include<iostream> #include…
