http://acm.hdu.edu.cn/showproblem.php?pid=3579 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4208    Accepted Submission(s): 1617 Problem Description One day I was shopping in the supermarket.…

不互质的中国剩余定理…… 链接http://acm.hdu.edu.cn/showproblem.php?pid=3579 #include<iostream>#include<stdio.h>#include<algorithm>#include<cmath>#include<iomanip>;}…

Hello Kiki Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1943    Accepted Submission(s): 693 Problem Description One day I was shopping in the supermarket. There was a cashier counting coins s…

Hello Kiki Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description One day I was shopping in the supermarket. There was a cashier counting coins seriously when a little kid running and singing "门前大桥下游过一…

好久没写什么数论,同余之类的东西了. 昨天第一次用了剩余定理解题,今天上百度搜了一下hdu中国剩余定理.于是就发现了这个题目. 题目的意思很简单.就是告诉你n个m[i],和n个a[i].表示一个数对m[i]取模的值为a[i]. 乍一看以为这个题目可以用中国剩余定理,但是看仔细了吗?这里的mi并没有说是互素的哦. 肿么办?只能用安叔以前说的解同余方程的那种土方法了. 上代码:(我稍微改进了一下,根据题目的具体情况). #include <iostream> #include <cstdio…

Hello Kiki Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4206    Accepted Submission(s): 1616 Problem Description One day I was shopping in the supermarket. There was a cashier counting coins…

<题目链接> 题目大意: 给你一些模数和余数,让你求出满足这些要求的最小的数的值. 解题分析: 中国剩余定理(模数不一定互质)模板题 #include<stdio.h> using namespace std; #define ll long long ll A[],B[];//B[i]为余数 ll dg,ans;//dg为A[i]的最小公倍数 ans 为最小解 void exgcd(ll a, ll b, ll &d, ll&x, ll &y) { ; y…

题意: 给定方程 res % 14 = 5 res % 57 = 56 求res 中国剩余定理裸题 #include<stdio.h> #include<string.h> #include<iostream> #include<algorithm> #include<math.h> #include<set> #include<queue> #include<vector> using namespace s…

HDU 3579 Hello Kiki Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3107    Accepted Submission(s): 1157 Problem Description One day I was shopping in the supermarket. There was a cashier counti…

HDU 1000 A + B Problem  I/O HDU 1001 Sum Problem  数学 HDU 1002 A + B Problem II  高精度加法 HDU 1003 Maxsum  贪心 HDU 1004 Let the Balloon Rise  字典树,map HDU 1005 Number Sequence  求数列循环节 HDU 1007 Quoit Design  最近点对 HDU 1008 Elevator  模拟 HDU 1010 Tempter of th…