Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 原题地址: Contains Duplicate 难度: Easy 题意: 判…

217. Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 题目大意: 给定一个整数数组,…

217. Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 思路:若整型数组中存在出现超过…

169. Majority Element /** * @param {number[]} nums * @return {number} */ var majorityElement = function(nums) { var hash = {}; var y=-1,z; //注意这里的方括号,利用变量访问对象属性时要用方括号 for(var i=0;i<=nums.length-1;i++){ if(hash[nums[i]]){ hash[nums[i]]++; }else{ hash[…

后面3个题都是限制在1-n的,所有可以不先排序,可以利用巧方法做.最后两个题几乎一模一样. 217. Contains Duplicate class Solution { public: bool containsDuplicate(vector<int>& nums) { int length = nums.size(); ) return false; sort(nums.begin(),nums.end()); ;i < length;i++){ ]) return tr…

217. Contains Duplicate[easy] Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 解法一: clas…

lc 217 Contains Duplicate 217 Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 字典统计词频 使用set 排序 日期 [LeetCode] 题目地址:https://leetcode.com/problems/contains-duplicate/ Total Accepted: 86528 Total Submissions: 209877 Difficulty: Easy 题目描述 Given an array of int…

#-*- coding: UTF-8 -*- class Solution(object):    def containsDuplicate(self, nums):        numsdic={}        for num in nums:            numsdic[num]=numsdic[num]+1 if num in numsdic else 1            if numsdic[num]>=2:                return True  …

Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Example 1: Input: [1,2,3,1] Output: tru…