[POJ3252]Round Numbers 试题描述 The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions s…

Round Numbers Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 7625   Accepted: 2625 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors',…

题目链接:http://poj.org/problem?id=3252 Round Numbers Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14640   Accepted: 5881 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (al…

题目传送门 Round Numbers Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 16439   Accepted: 6776 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scis…

Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such as who gets…

题目链接 POJ3252 题解 为什么每次写出数位dp都如此兴奋? 因为数位dp太苟了 因为我太弱了 设\(f[i][0|1][cnt1][cnt0]\)表示到二进制第\(i\)位,之前是否达到上界,前面已经有\(cnt1\)个\(1\),\(cnt0\)个\(0\)时的方案数 显然当\(cnt1 = 0\)时就不存在任何前导数字了 然后就记忆化搜索 分类讨论各种转移 [为什么我写得好麻烦QAQ是不是我姿势不对] #include<iostream> #include<cstdio>…

题目问区间有多少个数字的二进制0的个数大于等于1的个数. 用数学方法求出0到n区间的合法个数,然后用类似数位DP的统计思想. 我大概是这么求的,确定前缀的0和1,然后后面就是若干个0和若干个1的不重复全排列数.. 写得挺痛苦的..另外A[i][j]表示i个0和j个1的不重复全排列数,即A[i][j]=(i+j)!/i!/j!,这个可以从A[i-1][j]或A[i][j-1]求出来,这样就不用担心乘法溢出了. #include<cstdio> #include<cstring> us…

地址 拆成2进制位做dp记搜就行了,带一下前导0,将0和1的个数带到状态里面,每种0和1的个数讨论一下,累加即可. WA记录:line29. #include<iostream> #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #define dbg(x) cerr<<#x<<" = "<<x<…

题目大意: 求区间 \([x,y]\) 范围内有多少数的二进制表示中的'0'的个数 \(\ge\) '1'的个数. 解题思路: 使用 数位DP 解决这个问题. 我们设状态 f[pos][num0][num1][all0] 表示在: 当前所在数位为 pos : 当前选择的'0'的个数为 num0: 当前选择的'1'的个数为 num1: 到当前位位置是不是前面的数都是前导零(如果都是前导0则 all0==true,否则 all==false). 下的方案数. 我们开函数 dfs(int pos, i…

Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such as who gets…

Round Numbers DescriptionThe cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such…

Round Numbers poj3252 题目大意:求一段区间内Round Numbers的个数. 注释:如果一个数的二进制表示中0的个数不少于1的个数,我们就说这个数是Round Number.给定区间l,r<=$2\cdot 10^9$. 想法:又是一道数位dp裸题.我们先来设状态:dp[i]表示二进制表示下有i为而且第一位是1的Round Number的个数. 这题的特殊之处在于我们并不需要转移?因为我们可以直接求出任意的dp[i].显然,我们的i位数的第一位是1,所以,后面0的个数一定…

链接: https://vjudge.net/problem/POJ-3252 题意: The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbit…

[BZOJ1662][Usaco2006 Nov]Round Numbers 圆环数 Description 正如你所知,奶牛们没有手指以至于不能玩"石头剪刀布"来任意地决定例如谁先挤奶的顺序.她们甚至也不能通过仍硬币的方式. 所以她们通过"round number"竞赛的方式.第一头牛选取一个整数,小于20亿.第二头牛也这样选取一个整数.如果这两个数都是 "round numbers",那么第一头牛获胜,否则第二头牛获胜. 如果一个正整数N的二…

 组合数学...(每做一题都是这么艰难) Round Numbers Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 7607 Accepted: 2615 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, P…

Round Numbers Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10484 Accepted: 3831 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro…

题目链接:http://poj.org/problem?id=3252 题意: 一个数的二进制表示中0的个数大于等于1的个数则称作Round Numbers.求区间[L,R]内的 Round Numbers的个数. 思路: int c[N][N]; void init(){    int i,j;    FOR0(i,N)     {        c[i][0]=c[i][i]=1;        for(j=1;j<i;j++) c[i][j]=c[i-1][j-1]+c[i-1][j]; …

Description 正如你所知,奶牛们没有手指以至于不能玩“石头剪刀布”来任意地决定例如谁先挤奶的顺序.她们甚至也不能通过仍硬币的方式. 所以她们通过"round number"竞赛的方式.第一头牛选取一个整数,小于20亿.第二头牛也这样选取一个整数.如果这两个数都是 "round numbers",那么第一头牛获胜,否则第二头牛获胜. 如果一个正整数N的二进制表示中,0的个数大于或等于1的个数,那么N就被称为 "round number"…

Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 7558   Accepted: 2596 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo'…

1662: [Usaco2006 Nov]Round Numbers Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 147  Solved: 84[Submit][Status][Discuss] Description 正如你所知,奶牛们没有手指以至于不能玩“石头剪刀布”来任意地决定例如 谁先挤奶的顺序.她们甚至也不能通过仍硬币的方式. 所以她们通过"round number"竞赛的方式.第一头牛选取一个整数,小于20亿. 第二头牛也这样…

Round Numbers Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 8590   Accepted: 3003 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors',…

Round Numbers Time Limit : 4000/2000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 11   Accepted Submission(s) : 8 Problem Description The cows, as you know, have no fingers or thumbs and thus are unable to play Sci…

BZOJ_1662_[Usaco2006 Nov]Round Numbers 圆环数_数位DP Description 正如你所知,奶牛们没有手指以至于不能玩“石头剪刀布”来任意地决定例如谁先挤奶的顺序.她们甚至也不能通过仍硬币的方式. 所以她们通过"round number"竞赛的方式.第一头牛选取一个整数,小于20亿.第二头牛也这样选取一个整数.如果这两个数都是 "round numbers",那么第一头牛获胜,否则第二头牛获胜. 如果一个正整数N的二进制表示中…

Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such as who gets…

The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such as who gets to be milked…

Round Numbers http://poj.org/problem?id=3252 Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 17293   Accepted: 7188 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also kn…

Round Numbers Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14947   Accepted: 6023 Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors',…

http://www.lydsy.com/JudgeOnline/problem.php?id=1662 这道题折腾了我两天啊-!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 果然还是太弱 !!!!!!!!!! 一直想不通啊.. 数位dp太神了 ..orz 看题解各种不会啊...(神犇们的题解都说,裸数位dp,没了QAQ) 参考论文 刘聪<浅谈数位类统计问题> 在信息学竞赛中,有这样一类问题:求给定区间中,满足给定条件的某个 D 进制数或此类数的数量.所求的限定条件往往与数…

Description The cows, as you know, have no fingers or thumbs and thus are unable to play Scissors, Paper, Stone' (also known as 'Rock, Paper, Scissors', 'Ro, Sham, Bo', and a host of other names) in order to make arbitrary decisions such as who gets…

1265. Round Numbers(rndnum.pas/c/cpp) (File IO): input:rndnum.in output:rndnum.out Time Limits: 1000 ms  Memory Limits: 65536 KB  Detailed Limits   Goto ProblemSet Description        正如你所知,奶牛们没有手指以至于不能玩“石头剪刀布”来任意地决定例如谁先挤奶的顺序.她们甚至也不能通过仍硬币的方式.       所以…