poj 2488A Knight's Journey】的更多相关文章

#include<cstdio> #include<cstring> #define MAXN 26 using namespace std; ,,-,,-,,-,}; ,-,-,-,,,,}; int vis[MAXN][MAXN]; int lu[MAXN][MAXN]; int p,q; bool flag; void dfs(int i,int j,int step) { int x,y; vis[i][j]=step; if(step==p*q) { flag=true;…
A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 31702   Accepted: 10813 Description Background  The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey …
题目链接:http://vjudge.net/contest/view.action?cid=51369#problem/A   (A - Children of the Candy Corn) http://poj.org/problem?id=2488   (A Knight's Journey) (不知道为什么,名字竟然不同哇~~~~还是poj 改名改得好) 题目意思:给出一个p * q 的棋盘,行用阿拉伯数字1,2,...,p-1, p 来表示,列从大写字母'A'开始表示.我这里为了简化…
POJ 2488 -- A Knight's Journey(骑士游历) 题意: 给出一个国际棋盘的大小,判断马能否不重复的走过所有格,并记录下其中按字典序排列的第一种路径. 经典的“骑士游历”问题 输入:第一行,整数n,接下来是n行,每一行为p和q,p为行数,q为列数,p用1...p编号,q用A...Q编号 马的走法:每步棋先横走或直走一格,然后再往外斜走一格;或者先斜走一格,最后再往外横走或竖走一格(即走"日"字).可以越子,没有中国象棋中的"蹩马腿"限制. 解…
A Knight's Journey Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 35564 Accepted: 12119 Description Background The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey around…
A Knight's Journey Time Limit: 1000MSMemory Limit: 65536K Total Submissions: 34633Accepted: 11815 Description BackgroundThe knight is getting bored of seeing the same black and white squares again and again and has decided to make a journeyaround the…
A Knight's Journey Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 66   Accepted Submission(s) : 27 Problem Description Background The knight is getting bored of seeing the same black and white…
A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 35342   Accepted: 12051 Description Background  The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey …
题目链接:http://poj.org/problem?id=2488 A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 36695   Accepted: 12462 Description Background The knight is getting bored of seeing the same black and white squares again and again…
迷宫问题(bfs) POJ - 3984   #include <iostream> #include <queue> #include <stack> #include <cstring> using namespace std; /*广度优先搜索*/ /*将每个未访问过的邻接点进队列,然后出队列,知道到达终点*/ typedef class { public: int x; int y; }coordinate; ][]; //迷宫 ][] = { {…