2007/2008 ACM International Collegiate Programming Contest University of Ulm Local Contest Problem F: Frequent values You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several querie…

/************************************************************ 题目: Frequent values(poj 3368) 链接: http://poj.org/problem?id=3368 题意: 给出n个数和Q个询问(l,r),对于每个询问求出(l,r)之 间连续出现次数最多的次数 算法: RMQ 思路: 借助数组f[i].表示第i位前面有f[i]个相同的数.对于 每个区间(l,r).暴力求前面几个相同的数.然后在用RMQ 求后面…

Problem F: Frequent values You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequen…

Frequent values 题意是不同颜色区间首尾相接,询问一个区间内同色区间的最长长度. 网上流行的做法,包括翻出来之前POJ的代码也是RMQ做法,对于序列上的每个数,记录该数向左和向右延续的最远位置,那么对于一个查询Q(L, R),它的答案就分成了三种情况right(L) - L,R - left(R)以及Q(L+right(L),R-left(R)). 这里给出一个线段树做法,在线段树的节点上维护3个量:l_value, r_value, value分别表示以左端点为起始点,以右端点为…

UVa 11235 Frequent values Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11241   Accepted: 4110 Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several qu…

Frequent values Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1146    Accepted Submission(s): 415 Problem Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasin…

Frequent values You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value amo…

2007/2008 ACM International Collegiate Programming Contest University of Ulm Local Contest Problem F: Frequent values You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several querie…

Frequent values Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 13516   Accepted: 4971 Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries cons…

Frequent values TimeLimit:3000Ms , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among the integers ai , ... , aj.…

Frequent values Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14742   Accepted: 5354 Description You are given a sequence of n integersa1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consi…

传送门:http://poj.org/problem?id=3368 Frequent values Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 23016   Accepted: 8060 Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that,…

D. Frequent values Time Limit: 3000ms Case Time Limit: 3000ms Memory Limit: 131072KB   64-bit integer IO format: %lld      Java class name: Main   2007/2008 ACM International Collegiate Programming Contest University of Ulm Local Contest Problem F: F…

                                                     Frequent values Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 15229   Accepted: 5550 Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In…

RMQ算法 简单来说,RMQ算法是给定一组数据,求取区间[l,r]内的最大或最小值. 例如一组任意数据 5 6 8 1 3 11 45 78 59 66 4,求取区间(1,8)  内的最大值.数据量小时,只需遍历一遍就可以,数据量一大时就容易时间超限,RMQ算法是一种高效算法,和线段树差不多(当没有数据的实时更新时),当然两者都需要预处理. 定义映射f(i,j)=x,即以i为起点,长度为2j 区间内的最大最小值,显而易见f(i,0)为该数本身,那么求f(i,j+1)时: 可得公式 f(i,j)=…

Frequent values Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14764   Accepted: 5361 Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries cons…

Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among t…

Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among t…

Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among t…

Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 16537   Accepted: 5981 Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indice…

Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among t…

描述 You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, determine the most frequent value among the intege…

题目链接:http://poj.org/problem? id=3368 Description You are given a sequence of n integers a1 , a2 , ... , an in non-decreasing order. In addition to that, you are given several queries consisting of indices i and j (1 ≤ i ≤ j ≤ n). For each query, dete…

题目大概说给一个递增序列,询问区间出现最多的数. 用莫队算法比较直观,虽然应该会T..好像也可以主席树..不过题目给的序列是有序的,因而相同的数会聚在一起. 考虑把序列分成一段一段,使每段都包含极大的相同的数字 这样对于每一个区间查询: 可能这个区间左边或右边没有包含完整的一段,而其长度在段里对左或右端点进行二分查找就知道了 而除去两边不完整的,还要求出中间若干完整段的最大长度,这个就是用RMQ来快速解决了 于是这题就能这样解决了. #include<cstdio> #include<c…

大白书上的例题,具体讲解见大白书,最好用用一个Log数组直接求k,这样就是纯O(1)了 #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using namespace std; #define N 100003 int a[N],num[N],le[N],ri[N],cnt[N]; ],n,type; vo…

题目大意:在一个长度为n的不降序列中,有m次询问,每次询问(i,j)表示在区间(i,j)中找出出现次数最多的元素的出现次数. 题目分析:因为序列有序,可以将序列分段,并且记录每段的元素个数.每一个元素所属的段num(i).每一个元素所属段的左端点l(i)及右端点r(i).那么对于每次询问: ans(i,j)＝max(max(r(i)-i+1,j-l(j)+1),rmq(num(i)+1,num(j)-1)). ans(i,j)＝r-j+1 (如果i与j属于同一段) 代码如下: # include…

#include<cstdio> #include<cstring> ; const int inf=0x3f3f3f3f; inline int max(int x,int y) { return x>y?x:y; } int a[maxn]; int left[maxn]; int right[maxn]; int num[maxn]; ]; void init() { memset(a,,sizeof a); memset(left,-,sizeof left); me…

题目:http://poj.org/problem?id=3368 题意:给定n个数,顺序为非下降,询问某个区间内的数出现最多的数的 出现次数.. 大白书上的 例题..算是RMQ变形了, 对 原数组重新分段,并标记相同的个数为 该段的数值,然后RMQ... #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <algorithm>…

范围最值问题,O(nlogn)的预处理,O(1)的查询. 这个题就是先对这些数列进行游程编码,重复的元素只记录下重复的次数. 对于所查询的[L, R]如果它完全覆盖了某些连续的重复片段,那么查询的就是这几种元素重复最多的次数,也就是RMQ. 如果[L, R]还覆盖了某一部分边界,也要单独计算取最大值. 还有个特殊情况就是查询区间都在某一个元素的重复片段中,答案直接就是R-L+1 #include <cstdio> #include <vector> #include <alg…

<算法竞赛入门经典-训练指南>P198 记录一下区间的左右边界就可以了 #include <iostream> #include <stack> #include <queue> #include <cstdio> #include <cstdlib> #include <cmath> #include <set> #include <vector> #include <cstring>…