717. 1比特与2比特字符 LeetCode717. 1-bit and 2-bit Characters 题目描述 有两种特殊字符.第一种字符可以用一比特0来表示.第二种字符可以用两比特(10 或 11)来表示. 现给一个由若干比特组成的字符串.问最后一个字符是否必定为一个一比特字符.给定的字符串总是由0结束. 示例 1: 输入: bits = [1, 0, 0] 输出: True 解释: 唯一的编码方式是一个两比特字符和一个一比特字符.所以最后一个字符是一比特字符. 示例 2: 输入: b…

problem 717. 1-bit and 2-bit Characters 题意:solution1: class Solution { public: bool isOneBitCharacter(vector<int>& bits) { ; ) { ) i+=; ; } ; } }; solution2:根据数组的特性计算. class Solution { public: bool isOneBitCharacter(vector<int>& bits)…

https://leetcode.com/problems/1-bit-and-2-bit-characters/description/ We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented…

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented by several bits. Return whether the last character must be a one-bit c…

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented by several bits. Return whether the last character must be a one-bit c…

［抄题］: We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented by several bits. Return whether the last character must be a one…

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented by several bits. Return whether the last character must be a one-bit c…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历 日期 题目地址:https://leetcode.com/problems/1-bit-and-2-bit-characters/description/ 题目描述 We have two special characters. The first character can be represented by one bit 0. The s…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: bool isOneBitCharacter(vector<int>& bits) { int sz=bits.size(); ; ) { ) i+=; else i+=; } ; } }; 这个题,从前向后扫,只要当前位为1,则不用管下一位是啥,必然要构成2位,所以当前位为1时,…

package y2019.Algorithm.array; /** * @ProjectName: cutter-point * @Package: y2019.Algorithm.array * @ClassName: IsOneBitCharacter * @Author: xiaof * @Description: TODO 717. 1-bit and 2-bit Characters * We have two special characters. The first charac…