PAT 1065 A+B and C (64bit)】的更多相关文章

1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065 A+B and C (64bit) (20 分)   Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists o…
1065 A+B and C (64bit)(20 分) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, eac…
1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
1065 A+B and C (64bit) (20 分)   Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists o…
1065 A+B and C (64bit) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each cons…
这次的题目来源是 2013 年 10 月 7 日下午的浙大计算机研究生招生机试题. 这次题目的难度,按姥姥的说法是:『比普通的 PAT 要难了 0.5 个点.我是把自己的题目从 1.0 到 5.0 以 0.5 的间距分难度级别的,PAT(A)难度一般在 1.5-4.5 之间,保研考试一般在 2.0-5.0 之间.PAT(B)大概是 1.0-2.5 的难度.』. 个人认为,其中 1066 模拟 AVL 插入的实现有些细节容易弄错,而 1068 只要会简单的 DP,也就没有问题了,1065 和 10…
pat 1065 A+B and C                                          主要是注意一下加法溢出的情况,不要试图使用double,因为它的精度是15~16位,不能满足精度要求,代码如下: #include<cstdio> #include<climits> #include<cmath> //double精度为15~16位,不能满足精度要求 int main() { int testNum; scanf("%d&q…
1065 A+B and C (64bit) (20 分) Given three integers A, B and C in [−2^​63​​,2​^63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow,…
1065 A+B and C (64bit)(20 分) Given three integers A, B and C in [−2​63​​,2​63​​], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, eac…
1065. A+B and C (64bit) (20) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 HOU, Qiming Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the po…
题目链接 https://www.patest.cn/contests/pat-a-practise/1065 思路 因为 a 和 b 都是 在 long long 范围内的 但是 a + b 可能会溢出 long long 但是 不会溢出 long double 所以 用long double 就能轻松解决了 或者 用大数加法 也行 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #includ…
题目 Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10).  Then T test cases follow, each consists of a single lin…
因为会溢出,因此判断条件需要转化.变成b>c-a #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; long long a,b,c; int main() { int T; scanf("%d",&T);…
第一眼以为是大数据,想套个大数据模板,后来发现不需要.因为A.B.C的大小为[-2^63, 2^63],用long long 存储他们的值和sum. 接下来就是分类讨论:如果A > 0, B < 0 或者 A < 0, B > 0,sum不会溢出,直接和C判断比较即可.如果A > 0, B > 0,sum可能会溢出, 溢出的话为负数,所以sum < 0时候说明溢出了,那么肯定是大于C的.如果A < 0, B < 0,sum可能会溢出,同理,sum &g…
代码: import java.util.*; import java.math.*; public class Main { public static void main(String args[]) { Scanner cin=new Scanner(System.in); int t=cin.nextInt(); for(int i=1;i<=t;i++) { BigInteger a,b,c; a=cin.nextBigInteger(); b=cin.nextBigInteger()…
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three…
题意: 输入三个整数A,B,C(long long范围内),输出是否A+B>C. trick: 测试点2包括溢出的数据,判断一下是否溢出即可. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int t; ci…
题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1065 思路分析: 1)对a+b造成的long long 类型的数据溢出进行特殊处理: a>0 && b>0 && a+b<=0 :则a+b必大于c a<0 && b<0 && a+b>=0 :则a+b必小于c #include <stdio.h> #include <stdlib.h&…
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line co…
1065 单身狗(25 分) "单身狗"是中文对于单身人士的一种爱称.本题请你从上万人的大型派对中找出落单的客人,以便给予特殊关爱. 输入格式: 输入第一行给出一个正整数 N(≤ 50 000),是已知夫妻/伴侣的对数:随后 N 行,每行给出一对夫妻/伴侣--为方便起见,每人对应一个 ID 号,为 5 位数字(从 00000 到 99999),ID 间以空格分隔:之后给出一个正整数 M(≤ 10 000),为参加派对的总人数:随后一行给出这 M 位客人的 ID,以空格分隔.题目保证无人…
#include<stdio.h> #include <math.h> int main() { long long a,b,c,sum; int n,i; while(scanf("%d",&n)!=EOF) { ;i<=n;i++) { getchar(); scanf("%lld%lld%lld",&a,&b,&c); sum = a + b; int ifis; &&b>&a…
Given three integers A, B and C in [-2^63, 2^63], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line…
“单身狗”是中文对于单身人士的一种爱称.本题请你从上万人的大型派对中找出落单的客人,以便给予特殊关爱. 输入格式: 输入第一行给出一个正整数N(<=50000),是已知夫妻/伴侣的对数:随后N行,每行给出一对夫妻/伴侣——为方便起见,每人对应一个ID号,为5位数字(从00000到99999),ID间以空格分隔:之后给出一个正整数M(<=10000),为参加派对的总人数:随后一行给出这M位客人的ID,以空格分隔.题目保证无人重婚或脚踩两条船. 输出格式: 首先第一行输出落单客人的总人数:随后第二…
https://pintia.cn/problem-sets/994805260223102976/problems/994805266942377984 “单身狗”是中文对于单身人士的一种爱称.本题请你从上万人的大型派对中找出落单的客人,以便给予特殊关爱. 输入格式: 输入第一行给出一个正整数 N(≤ 50 000),是已知夫妻/伴侣的对数:随后 N 行,每行给出一对夫妻/伴侣——为方便起见,每人对应一个 ID 号,为 5 位数字(从 00000 到 99999),ID 间以空格分隔:之后给出…
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line co…
“单身狗”是中文对于单身人士的一种爱称.本题请你从上万人的大型派对中找出落单的客人,以便给予特殊关爱. 输入格式: 输入第一行给出一个正整数N(<=50000),是已知夫妻/伴侣的对数:随后N行,每行给出一对夫妻/伴侣——为方便起见,每人对应一个ID号,为5位数字(从00000到99999),ID间以空格分隔:之后给出一个正整数M(<=10000),为参加派对的总人数:随后一行给出这M位客人的ID,以空格分隔.题目保证无人重婚或脚踩两条船. 输出格式: 首先第一行输出落单客人的总人数:随后第二…
Given three integers A, B and C in [-263, 263], you are supposed to tell whether A+B > C. Input Specification: The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line co…
AC代码 #include <cstdio> int main() { #ifdef ONLINE_JUDGE #else freopen("1.txt", "r", stdin); #endif // ONLINE_JUDGE char str[2][10] = {"false", "true"}; int n, tcase = 1; scanf("%d", &n); for(int…
Given three integers A, B and C in [−], you are supposed to tell whether A+B>C. Input Specification: The first line of the input gives the positive number of test cases, T (≤). Then T test cases follow, each consists of a single line containing three…