题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1548 题目大意:升降电梯,先给出n层楼,然后给出起始的位置,即使输出从A楼道B楼的最短时间. 注意的几点 (1)每次按一下,只能表示上或者是下,然后根据输入的看是上几层或者是下几层. (2)注意不能到底不存在的楼层. 详见代码. #include <iostream> #include <cstdio> using namespace std; ; ][],node[],vis[],M…

A strange lift http://acm.hdu.edu.cn/showproblem.php?pid=1548 Problem Description There is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every floor.The lift have just two buttons: up and…

题目大意: 电梯有两个选项向上或向下,每层楼有一个参数ki,代表电梯可以再该楼层的基础上向上或向下移动ki层,限制条件是向上不能超过楼层总数n,向下不能少于一.输入总层数n和当前所在层数以及目标层数,然后是n个数分别代表第i层的移动范围.输出最少移动次数,若不可达,输出-1. 解题思路: 1.用Dijkstra算法,首先构建邻接矩阵,注意在构造时,要考虑i-k[i]<1和i+k[i]>n,i代表当前所在层. #include<string.h> #include<stdio.…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1548 A strange lift Description There is a strange lift.The lift can stop can at every floor as you want, and there is a number $K_i(0 \leq K_i \leq N)$ on every floor.The lift have just two buttons: up…

题目链接: 传送门 A strange lift Time Limit: 1000MS     Memory Limit: 32768 K Description There is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every floor.The lift have just two buttons: up and…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1548 A strange lift Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 21754    Accepted Submission(s): 7969 Problem Description There is a strange li…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1548 There is a strange lift.The lift can stop can at every floor as you want, and there is a number Ki(0 <= Ki <= N) on every floor.The lift have just two buttons: up and down.When you at floor i,if yo…

A strange lift Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11341    Accepted Submission(s): 4289 Problem Description There is a strange lift.The lift can stop can at every floor as you want…

A strange lift Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8550    Accepted Submission(s): 3241 Problem Description There is a strange lift.The lift can stop can at every floor as you want,…

(￣▽￣)" //dijkstra算法, //只是有效边(即能从i楼到j楼)的边权都为1(代表次数1): //关于能否到达目标楼层b,只需判断最终lowtime[b]是否等于INF即可. #include<iostream> #include<cstdio> using namespace std; const int INF=10e7; ; int k,minn; int K[MAXN]; int cost[MAXN][MAXN]; int lowtime[MAXN];…