大数的位数设置很坑,设成700会越界,设成800会超空间,最后设成了750居然就过了.... #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define LL long long using namespace std; /* * 完全大数模板 * 输出cin>>a * 输出a.print(…

import java.math.BigInteger; import java.util.*; public class Main { public static void main(String []args) { Scanner cin=new Scanner(System.in); BigInteger a,b,c,d,m; int n; while(cin.hasNext()){ m=new BigInteger("1"); a=new BigInteger("1&…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1250 Hat's Fibonacci Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.$F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n >…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1250 Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12952    Accepted Submission(s): 4331 Problem Description A Fibonacci sequence…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14776    Accepted Submission(s): 4923   Problem Description A Fibonacci sequence is calculated by adding the previous two members…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1250 hdu1250: Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9442    Accepted Submission(s): 3096 Problem Description A Fibonacci…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5800    Accepted Submission(s): 1926 Problem Description A Fibonacci sequence is calculated by adding the previous two members the…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9394    Accepted Submission(s): 3065 Problem Description A Fibonacci sequence is calculated by adding the previous two members the…

Mathematician QSC Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 229    Accepted Submission(s): 114 Problem Description QSC dream of becoming a mathematician, he believes that everything in t…

Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 12284    Accepted Submission(s): 4124 Problem Description A Fibonacci sequence is calculated by adding the previous two members t…

HDU 1588 Gauss Fibonacci(矩阵高速幂+二分等比序列求和) ACM 题目地址:HDU 1588 Gauss Fibonacci 题意:  g(i)=k*i+b;i为变量.  给出k,b,n,M,问( f(g(0)) + f(g(1)) + ... + f(g(n)) ) % M的值. 分析:  把斐波那契的矩阵带进去,会发现这个是个等比序列. 推倒: S(g(i)) = F(b) + F(b+k) + F(b+2k) + .... + F(b+nk) // 设 A = {1…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

//  继续大数,哎.. Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your tas…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

题目 java做大数的题,真的是神器,来一道,秒一道~~~ import java.io.*; import java.util.*; import java.math.*; public class Main { /** * @xqq */ public BigInteger an(int n) { BigInteger e; BigInteger a = BigInteger.valueOf(1); BigInteger b = BigInteger.valueOf(1); BigInteg…

本文参考: https://www.cnblogs.com/GerynOhenz/p/8727415.html kuangbin的ACM模板(新) 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4347 Problem Description The course of Software Design and Development Practice is objectionable. ZLC is facing a serious problem…

http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…

http://acm.hdu.edu.cn/showproblem.php?pid=1533 这道题直接用了模板 题意:要构建一个二分图,家对应人,连线的权值就是最短距离,求最小费用 要注意void init(int n) 这个函数一定要写 一开始忘记写这个WA了好几发 还有这个题很容易T掉,赋值建图要简化,一开始构建成网络流那种图一直T #include <stdio.h> #include <string.h> #include <iostream> #includ…

http://acm.hdu.edu.cn/showproblem.php?pid=4280 题意:在最西边的点走到最东边的点最大容量. 思路:ISAP模板题,Dinic过不了. #include <cstdio> #include <algorithm> #include <iostream> #include <cstring> #include <string> #include <cmath> #include <que…

参考iwtwiioi的模板写出来的.上午gty讲的并没有听懂,只好自己慢慢对着模板理解. 在HDU上为什么相同的程序提交有时T有时A!!! 奉上sth神犇的模板(不是这道题): var ch:char; q,g,num:array [0..500001] of longint; st:string; son:array [0..500001,'a'..'z'] of longint; ts:array [0..1000001] of char; l,s,t,n,i,j,m,k,ans,head,…

Fibonacci Check-up Problem Description Every ALPC has his own alpc-number just like alpc12, alpc55, alpc62 etc.As more and more fresh man join us. How to number them? And how to avoid their alpc-number conflicted? Of course, we can number them one by…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1288 去买茶,需要正好的钱才行,另外花的钱的个数最多  其实是一个简单的贪心问题,小的多取一点,多的少取一点.反着想,算出超出部分数量. 代码: #include <stdio.h> #include <string.h> #include <math.h> #include <algorithm> #include <iostream> #incl…

Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2516 Problem Description 1堆石子有n个,两人轮流取.先取者第1次可以取任意多个,但不能全部取完.以后每次取的石子数不能超过上次取子数的2倍.取完者胜.先取者负输出"Second win".先取者胜输出"First win".   Input 输入有多组.每组第1行是2<=n<2^31. n=0退出.   Output 先取者负输出&qu…

BUPT2017 wintertraining(16) #5 A HDU - 1021 题意 There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2). 输入n,若F(n)能被3整除,输出yes,否则no 题解 列一下前几项F(i)可以发现n%4==2则是yes,否则no. 代码 #include <cstdio> #include <cstring…

http://acm.hdu.edu.cn/showproblem.php?pid=5651 题意:生成回文串.输出所有回文串的可能数. 题解:mod除法会损失高位,用逆元来代替除法,模板如下 ac代码: #include<stdio.h> #include<string.h> #include<iostream> #include<string> using namespace std; ; int num[maxn]; //char s[maxn]; t…

http://acm.hdu.edu.cn/showproblem.php?pid=2089 题意:求区间内不包含4和连续62的数的个数. 思路: 简单的数位dp模板题.给大家推荐一个好的讲解博客.http://blog.csdn.net/mosquito_zm/article/details/75226543 #include<iostream> #include<algorithm> #include<cstring> #include<cstdio>…

http://acm.hdu.edu.cn/showproblem.php?pid=2222 题意:给出多个单词,最后再给出一个模式串,求在该模式串中包含了多少个单词. 思路: AC自动机的模板题. #include<iostream> #include<algorithm> #include<cstring> #include<cstdio> #include<vector> #include<stack> #include<…