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#include <bits/stdc++.h> using namespace std; template <typename T> T inverse(T a, T m) { T u = 0, v = 1; while (a != 0) { T t = m / a; m -= t * a; swap(a, m); u -= t * v; swap(u, v); } assert(m == 1); return u; } template <typename T> c…
1 Introduction Modular arithmetic is a fundamental tool in modern algebra systems. In conjunction with the Chinese remainder theorem it serves as the workhorse in several algorithms computing the gcd, resultant etc. Moreover, it can serve as a very e…
题目: 电音之王 题解: 求数列前n项相乘并取模 思路: ①.这题的乘法是爆long long的,可以通过快速幂的思想去解决(按数位对其中的一个数进行剖分).当然你的乘法会多出一个log的复杂度... ②.O(1)快速乘:一种O(1)复杂度求解整数相乘取模的思路(它对于64位的整型也是适用的): 来自2009年国家集训队论文:骆可强:<论程序底层优化的一些方法与技巧> (参考中附原文链接) typedef long long ll; #define MOL 123456789012345LL…
I am Nexus Master!  The 13th Zhejiang University Programming Contest 参见:http://www.bnuoj.com/bnuoj/problem_show.php?pid=29137 题意就理解错了!!! 之后乱搞就也错了!!! Current Server Time: 2013-08-30 23:29:55 I am Nexus Master! Time Limit: 2000ms Memory Limit: 65536KB…
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链接:http://www.bnuoj.com/bnuoj/problem_show.php?pid=25585 Current Server Time: 2013-08-27 20:42:26 Robots on a grid Time Limit: 3000ms Memory Limit: 65536KB   64-bit integer IO format: %lld      Java class name: Main Prev Submit Status Statistics Disc…
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