Human Gene Functions Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3103    Accepted Submission(s): 1761 Problem Description It is well known that a human gene can be considered as a sequence,…
以下程序在hadoop1.2.1上测试成功. 本例先将源代码呈现,然后详细说明执行步骤,最后对源代码及执行过程进行分析. 一.源代码 package org.jediael.hadoopdemo.wordcount; import java.io.IOException; import java.util.StringTokenizer; import org.apache.hadoop.conf.Configuration; import org.apache.hadoop.fs.Path;…
Sudoku Killer Problem Description 自从2006年3月10日至11日的首届数独世界锦标赛以后,数独这项游戏越来越受到人们的喜爱和重视. 据说,在2008北京奥运会上,会将数独列为一个单独的项目进行比赛,冠军将有可能获得的一份巨大的奖品---HDU免费七日游外加lcy亲笔签名以及同hdu acm team合影留念的机会. 所以全球人民前仆后继,为了奖品日夜训练茶饭不思.当然也包括初学者linle,不过他太笨了又没有多少耐性,只能做做最最基本的数独题,不过他还是想得到…
一.什么是正则表达式 正则表达式,又称正规表示法,是对字符串操作的一种逻辑公式.正则表达式可以检测给定的字符串是否符合我们定义的逻辑,也可以从字符串中获取我们想要的特定部分.它可以迅速地用极简单的方式达到字符串的复杂控制. 二.正则表达式的语法 看一个过滤纯数字的例子 - (BOOL)validateNumber:(NSString *) textString { NSString* number=@"^[0-9]+$"; NSPredicate *numberPre = [NSPre…
对于Lucene的索引过程,除了将词(Term)写入倒排表并最终写入Lucene的索引文件外,还包括分词(Analyzer)和合并段(merge segments)的过程,本次不包括这两部分,将在以后的文章中进行分析. Lucene的索引过程,很多的博客,文章都有介绍,推荐大家上网搜一篇文章:<Annotated Lucene>,好像中文名称叫<Lucene源码剖析>是很不错的. 想要真正了解Lucene索引文件过程,最好的办法是跟进代码调试,对着文章看代码,这样不但能够最详细准确…
我们知道通过Sql代理,可以实现数据库的定时备份功能:当数据库里的数据库很多时,备份一个数据库需要建立对应的定时作业,相对来说比较麻烦: 还好,微软自带的osql工具,比较实用,通过在命令行里里输入命令,也能实现数据库备份的功能:如果能通过sql语句来生成一个批处理文件,那就方便了: 下面即是生成批处理文件的sql脚本,通过它可以实现:运行一个批处理文件,备份数据库服务器上的所有数据库到指定目录. 生成批量备份脚本: /**************************************…
哈密顿绕行世界问题 Time Limit : 3000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 66   Accepted Submission(s) : 33 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description 一个规则的实心十二面体,它的 20个顶点标出世界著名的…
A Plug for UNIX Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 14786 Accepted: 4994 Description You are in charge of setting up the press room for the inaugural meeting of the United Nations Internet eXecutive (UNIX), which has an interna…
May Day Holiday Time Limit: 2 Seconds Memory Limit: 65536 KB As a university advocating self-learning and work-rest balance, Marjar University has so many days of rest, including holidays and weekends. Each weekend, which consists of Saturday and Sun…
FatMouse' Trade Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 42953    Accepted Submission(s): 14336 Problem Description FatMouse prepared M pounds of cat food, ready to trade with the cats g…
加载bcmdhd模块:# modprobe bcmdhd 如果你希望开启 AP 模式,那么:# modprobe bcmdhd op_mode=2 在/etc/modules文件内添加bcmdhd op_mode=2,以实现bcmdhd模块的开机自动加载. hostapd安装与配置 参考链接:http://wireless.kernel.org/en/users/Documentation/hostapd#Using_your_distributions_hostapd 安装hostapd: 1…
//初始化textfield并设置位置及大小   UITextField *text = [[UITextField alloc]initWithFrame:CGRectMake(20, 20, 130, 30)];   //设置边框样式,只有设置了才会显示边框样式   text.borderStyle = UITextBorderStyleRoundedRect; typedef enum {     UITextBorderStyleNone,      UITextBorderStyleL…
A计划 Time Limit : 3000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 76   Accepted Submission(s) : 37 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description 可怜的公主在一次次被魔王掳走一次次被骑士们救回来之后,而今,不幸的…
4273: 玩具 Time Limit: 1 Sec  Memory Limit: 128 MB Submit: 700  Solved: 129 Description 商店有n个玩具,第i个玩具有价格a[i]和快乐值b[i].有一天,小王来到商店想买一些玩具,商店老板告诉他,如果他买的所有玩具的位置是连续的,那么老板答应小王购买的所有玩具中某一个可以免费.小王接受老板的提议,他现在有零花钱k可以用来买玩具,那么他能获得的最大的快乐值是多少. Input 第一行给测试总数T(T <= 100)…
nutch将从网页中抓取到的信息放入hbase数据库中,默认情况下表名为$crawlId_webpage,但表中的内容以16进制进行表示,直接scan或者通过Java API进行读取均只能读取到16进制信息.     因此nutch提供了readdb选项进行数据获取,将表中的内容读取到一个文本中.  具体用法为: $ bin/nutch readdb Usage: WebTableReader (-stats | -url [url] | -dump <out_dir> [-regex reg…
IIS上在主站点下搭建虚拟目录后,子站点中的<system.web>节点与主站点的<system.web>冲突解决方法: 在主站点的<system.web>上一级添加父节点: <location path="." allowOverride="false" inheritInChildApplications="false">     <system.web>         <!…
To Check current users permissions using Ecmascript\Javascript client object model SharePoint 2010. function checkifUserHasEditPermissions() { context = new SP.ClientContext.get_current(); web = context.get_web(); this._currentUser = web.get_currentU…
If you understand the comments below, never will you make mistakes with binary search! thanks to A simple CPP solution with lower_bound and C++ O(logn) Binary Search that handles duplicate, thanks to phu1ku 's answer on the second post. http://en.cpp…
一:导言 有些WEB开发者,会引用一个JQuery类库,然后在网页上写一写$("#"),$("."),写了几年就对别人说非常熟悉JQuery.我曾经也是这样的人,直到有一次公司里的技术交流,我才改变了自己对自己的看法. 二:普及JQuery知识 知识1:用JQuery写插件时,最核心的方法有如下两个: $.extend(object) 可以理解为JQuery 添加一个静态方法. $.fn.extend(object) 可以理解为JQuery实例添加一个方法. 基本的…
实现代码: $.extend($.fn.tabs.methods, { /** * 绑定双击事件 * @param {Object} jq * @param {Object} caller 绑定的事件处理程序 */ bindDblclick: function(jq, caller){ return jq.each(function(){ var that = this; $(this).children("div.tabs-header").find("ul.tabs&qu…
一个原则是:应该尽量少的使用parallelfor, 因为parallel for也需要时间开销.即: (1)如果外层循环次数远远小于内层循环次数,内层循环较多时,将parallel for加在内层循环. 示例代码: int a=0; int b=0; inline void openmpTest2(int thread_num) { for(int i=0;i<100;i++) { #pragma omp parallel for num_threads(thread_num) for(int…
1.       问题 C++如何实现不能被继承的类,即终结类.Java中有final关键字修饰,C#中有sealed关键字修饰,而C++目前还没有类似的关键字来修饰类实现终结类,需编程人员手动实现.   2.       解决方法 基本思路:由于任何派生类的对象在创建的时候,都必需在派生类的构造函数中调用父类的构造函数.所以,只要类的构造函数在子类中无法被访问,那么就阻止了该类被继承,实现终结类. 如果将一个类的构造函数声明为私有(private),可以阻止该类进一步派生,但是该类也无法直接实…
Dungeon Master Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20995 Accepted: 8150 Description You are trapped in a 3D dungeon and need to find the quickest way out! The dungeon is composed of unit cubes which may or may not be filled wit…
Black Box Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 8754 Accepted: 3599 Description Our Black Box represents a primitive database. It can save an integer array and has a special i variable. At the initial moment Black Box is empty an…
Demacia of the Ancients Time Limit: 2 Seconds Memory Limit: 65536 KB There is a popular multiplayer online battle arena game called Demacia of the Ancients. There are lots of professional teams playing this game. A team will be approved as Level K if…
Capture the Flag Time Limit: 2 Seconds Memory Limit: 65536 KB Special Judge In computer security, Capture the Flag (CTF) is a computer security competition. CTF contests are usually designed to serve as an educational exercise to give participants ex…
Lunch Time Time Limit: 2 Seconds Memory Limit: 65536 KB The 999th Zhejiang Provincial Collegiate Programming Contest will be held in Marjar University. The canteen of Marjar University is making preparations for this grand competition. The canteen pr…
Beauty of Array Time Limit: 2 Seconds Memory Limit: 65536 KB Edward has an array A with N integers. He defines the beauty of an array as the summation of all distinct integers in the array. Now Edward wants to know the summation of the beauty of all…
Ace of Aces Time Limit: 2 Seconds Memory Limit: 65536 KB There is a mysterious organization called Time-Space Administrative Bureau (TSAB) in the deep universe that we humans have not discovered yet. This year, the TSAB decided to elect an outstandin…
Team Formation Time Limit: 3 Seconds Memory Limit: 131072 KB For an upcoming programming contest, Edward, the headmaster of Marjar University, is forming a two-man team from N students of his university. Edward knows the skill level of each student.…