69. Sqrt(x) Total Accepted: 93296 Total Submissions: 368340 Difficulty: Medium 提交网址: https://leetcode.com/problems/sqrtx/ Implement int sqrt(int x). Compute and return the square root of x. 分析: 解法1:牛顿迭代法(牛顿切线法) Newton's Method(牛顿切线法)是由艾萨克·牛顿在<流数法>(M…

Leetcode 69. Sqrt(x) Easy https://leetcode.com/problems/sqrtx/ Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncat…

Question 69. Sqrt(x) Solution 题目大意: 求一个数的平方根 思路: 二分查找 Python实现: def sqrt(x): l = 0 r = x + 1 while l < r: m = l + (r - l) // 2 if m * m > x: r = m else: l = m + 1 return l - 1…

Implement int sqrt(int x). Compute and return the square root of x. x is guaranteed to be a non-negative integer. Example 1: Input: 4 Output: 2 Example 2: Input: 8 Output: 2 Explanation: The square root of 8 is 2.82842..., and since we want to return…

Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:库函数 方法二:牛顿法 方法三:二分查找 日期 题目地址:https://leetcode.com/problems/sqrtx/description/ 题目描述 Implement int sqrt(int x). Compute and return the square root of x. x is guaranteed to be…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Implement int sqrt(int x). Compute and return the square root of x. (二)解题 实现sqrt(x),找到一个数,它的平方等于小于x的最接近x的数. class Solution { public: int mySqrt(int x) { int…

Implement int sqrt(int x). 思路: Binary Search class Solution(object): def mySqrt(self, x): """ :type x: int :rtype: int """ l = 0 r = x while l <= r: mid = (l+r)//2 if mid*mid < x: l = mid + 1 elif mid*mid > x: r = mi…

Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…

Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…

Sqrt(x) Implement int sqrt(int x). Compute and return the square root of x. 解法一:牛顿迭代法 求n的平方根,即求f(x)=x2-n的零点 设初始值为x0,注,不要设为0,以免出现除数为0,见后. 则过(x0,f(x0))点的切线为g(x)=f(x0)+f'(x0)*(x-x0) g(x)与x轴的交点为x1=x0-f(x0)/f'(x0) 递推关系为xn+1=xn-f(xn)/f'(xn) 当收敛时即为解. class…

可怕的同时考数值溢出和二分的酱油题之一,常在各种小公司的笔试中充当大题来给你好看... 题意很简单,在<二分查找综述>中有描述. 重点:使用简单粗暴的long long来避免溢出,二分均方根的答案来得到准确解. 当然这里的溢出不止是相乘的溢出,还有第六行那段代码的溢出,每次都会有几个解决问题的斗士牺牲在这里... class Solution { public: int mySqrt(int x) { , b = x; while(a <= b ){ ; if(mid * mid ==…

题目: Implement int sqrt(int x). Compute and return the square root of x. 链接:   http://leetcode.com/problems/sqrtx/ 题解: 求平方根. 二分法, Time Complexity - O(logn), Space Complexity - O(1) public class Solution { public int mySqrt(int x) { if(x <= 1) return x…

Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…

Implement int sqrt(int x). Compute and return the square root of x. 注意: 计算平方的时候可能会溢出,所以mid要定义为long 另外,二分法初始上限不可能超过n/2+1 class Solution { public: int mySqrt(int x) { ; +; while (left <= right) { ; ) * (mid + ) > x) { return mid; } else if (mid * mid…

［抄题］: Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. E…

Implement int sqrt(int x). Compute and return the square root of x, where x is guaranteed to be a non-negative integer. Since the return type is an integer, the decimal digits are truncated and only the integer part of the result is returned. Example…

Implement int sqrt(int x). Compute and return the square root of x. class Solution { public: int sqrt(int x) { // Start typing your C/C++ solution below // DO NOT write int main() function ) ; ) ; ; int large=x; ; while(small<large){ int a = x/temp;…

mycode   memory error class Solution(object): def mySqrt(self, x): """ :type x: int :rtype: int """ if x == 0 : return 0 if x == 1 or x==2 or x ==3 : return 1 for i in range(2,x//2): if i**2 > x : return i-1 参考: 1.但是下面这个可以…

[263] Ugly Number [Easy] 一个数的质因子只有2,3,5就叫丑数,写个函数判断丑数. //Author: Wanying //注意 0 和 1 的corner case, 你居然还没一次AC== //想好了再写,不然等着挂吧==!!!!! class Solution { public: bool isUgly(int num) { || num == ) { return num; } == ) { num = num / ; } == ) { num = num / ;…

2. Add Two Numbers https://leetcode.com/problems/add-two-numbers/description/ class Solution { public: ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode result(-); ListNode* current = &result; ; while(l1!=NULL || l2!=NULL){ ; ; if(l1!=NU…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…

刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…

算法思想 二分查找 贪心思想 双指针 排序 快速选择 堆排序 桶排序 搜索 BFS DFS Backtracking 分治 动态规划 分割整数 矩阵路径 斐波那契数列 最长递增子序列 最长公共子系列 0-1 背包 数组区间 字符串编辑 其它问题 数学 素数 最大公约数 进制转换 阶乘 字符串加法减法 相遇问题 多数投票问题 其它 数据结构相关 栈和队列 哈希表 字符串 数组与矩阵 1-n 分布 有序矩阵 链表 树 递归 层次遍历 前中后序遍历 BST Trie 图 位运算 参考资料 算法思想 二…

1.Two Sum Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 使用hash public int[] twoSum…

需要注意overflow,特别是Integer.MIN_VALUE这个数字. 需要掌握二分法. 不用除法的除法,分而治之的乘方 2. Add Two Numbers You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the tw…

Id Question Difficulty Frequency Data Structures Algorithms 1 Two Sum 2 5 array + set sort + two pointers 2 Add Two Numbers 3 4 linked list two pointers + math 3 Longest Substring Without Repeating Characters 3 2 string + hashtable two pointers 4 Med…

1. Two Sum Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution. Example: Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + n…

转载自:LeetCode Question Difficulty Distribution                 1 Two Sum 2 5 array sort           set Two Pointers   2 Add Two Numbers 3 4 linked list Two Pointers             Math   3 Longest Substring Without Repeating Characters 3 2 string Two Poin…