【[LeetCode] Range Sum Query - Immutable 区域和检索 - 不可变】的更多相关文章

[LeetCode] Range Sum Query - Immutable 区域和检索 - 不可变

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the array do…

[LeetCode] 303. Range Sum Query - Immutable 区域和检索 - 不可变

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the array do…

303 Range Sum Query - Immutable 区域和检索 - 不可变

给定一个数组,求出数组从索引 i 到 j  (i ≤ j) 范围内元素的总和,包含 i,  j 两点.例如:给定nums = [-2, 0, 3, -5, 2, -1],求和函数为sumRange()sumRange(0, 2) -> 1sumRange(2, 5) -> -1sumRange(0, 5) -> -3注意:    你可以假设数组不可变.    会多次调用 sumRange 方法.详见:https://leetcode.com/problems/range-sum-quer…

[LeetCode] Range Sum Query - Mutable 区域和检索 - 可变

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

[LeetCode] 307. Range Sum Query - Mutable 区域和检索 - 可变

Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2…

[LeetCode] Range Sum Query - Immutable & Range Sum Query 2D - Immutable

Range Sum Query - Immutable Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You…

[LeetCode] Range Sum Query - Immutable

The idea is fairly straightforward: create an array accu that stores the accumulated sum fornums such that accu[i] = nums[0] + ... + nums[i] in the initializer of NumArray. Then just return accu[j + 1] - accu[i] in sumRange. You may try the example i…

LeetCode——Range Sum Query - Immutable

Question Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. Example: Given nums = [-2, 0, 3, -5, 2, -1] sumRange(0, 2) -> 1 sumRange(2, 5) -> -1 sumRange(0, 5) -> -3 Note: You may assume that the…

[LeetCode] Range Sum Query 2D - Immutable 二维区域和检索 - 不可变

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, co…

[LeetCode] Range Sum Query 2D - Mutable 二维区域和检索 - 可变

Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). The above rectangle (with the red border) is defined by (row1, col1) = (2, 1) and (row2, co…