Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0.   Example 1: Input: 22 Output: 2 Explanation: 22 in binary is 0b10110. In t…

Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0.   Example 1: Input: 22 Output: 2 Explanation: 22 in binary is 0b10110. In t…

题目要求 Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0. 题目分析及思路 给定一个正整数,返回该数二进制形式中连续两个1的最长间隔.若是没有连续的两个1,则返回0.可将该数转成二进制形式,得到的结果…

// 我的代码 package Leetcode; /** * 199. Binary Tree Right Side View * address: https://leetcode.com/problems/binary-tree-right-side-view/ * Given a binary tree, imagine yourself standing on the right side of it, * return the values of the nodes you can…

LeetCode:Construct Binary Tree from Inorder and Postorder Traversal Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree.                                            …

LeetCode:Unique Binary Search Trees Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 分析:依次把每个节点作…

LeetCode: Validata Binary Search Tree Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree o…

Given a binary tree, return the postorder traversal of its nodes' values. Example: Input: [1,null,2,3] 1 \ 2 / 3 Output: [3,2,1] Follow up: Recursive solution is trivial, could you do it iteratively? --------------------------------------------------…

leetcode 199. Binary Tree Right Side View 这个题实际上就是把每一行最右侧的树打印出来,所以实际上还是一个层次遍历. 依旧利用之前层次遍历的代码,每次大的循环存储的是一行的节点,最后一个节点就是想要的那个节点 class Solution { public: vector<int> rightSideView(TreeNode* root) { vector<int> result; if(root == NULL) return resul…

Given a binary tree, you need to find the length of Longest Consecutive Path in Binary Tree. Especially, this path can be either increasing or decreasing. For example, [1,2,3,4] and [4,3,2,1] are both considered valid, but the path [1,2,4,3] is not v…