不重复的: 方法一 ［一句话思路］:排序之后用归并. ［一刷］: 根据返回方法的类型来判断corner case.判断空.0数组的corner case还不一样,得分开写 由于先排序了,nums1[i] < nums2[j]时,i++可以继续在nums2[j]里找是否有相同的 index=0时肯定不会重复,一定要插入 写法是Arrays.sort(nums1) 定义int i还不够,要初始化为0 并列用几个if可能会越界,还是用else if吧 result定义的长度不能是temp.length…

这两道题都是求两个数组之间的重复元素,因此把它们放在一起. 原题地址: 349 Intersection of Two Arrays :https://leetcode.com/problems/intersection-of-two-arrays/description/ 350 Intersection of Two Arrays II:https://leetcode.com/problems/intersection-of-two-arrays-ii/description/ 题目&&am…

283. Move Zeroes var moveZeroes = function(nums) { var num1=0,num2=1; while(num1!=num2){ nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0); } num1 = nums ; }); nums.forEach(function(x,y){ if(x===0){ nums.splice(y,1); nums.push(0);…

Given two arrays, write a function to compute their intersection. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4] Output: [9,4] Note: Each element in the result must be unique. The…

Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 我们可以使用两个指针来做,先给两个数组排序,然后用两个指针分别指向两个数组的…

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Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 题目标签:Hash Table 题目给了我们两个 array, 让我们找到在两…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:Java解法,HashSet 方法二:Python解法,set 日期 [LeetCode] 题目地址:https://leetcode.com/problems/intersection-of-two-arrays/ Difficulty: Easy 题目描述 Given two arrays, write a function to com…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. Subscribe to see which companies asked…

Given two arrays, write a function to compute their intersection. Example:Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order. 代码如下: public class Solution { public in…