LeetCode: Merge k Sorted Lists 解题报告】的更多相关文章

Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Show Tags 参考资料: http://blog.csdn.net/linhuanmars/article/details/19899259. SOLUTION 1: 使用分治法.左右分别递归调用Merge K sorted List,然后再使用merg…
题目地址: https://oj.leetcode.com/problems/merge-k-sorted-lists/ 题目内容: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ Merge k sorted linked lists and return it a…
Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Show Tags SOLUTION 1: 使用dummynode记录头节点的前一个,轻松完成,2分钟就AC啦! /** * Definition for singly-…
https://oj.leetcode.com/problems/merge-k-sorted-lists/ 归并K已经整理阵列,和分析算法的复杂. 解决报告:无论是不考虑优化,最简单的实现是要重新走路List<ListNode>.对当中每一个链表同当前链表做一遍类似于归并排序最后一步的merge操作. 算法复杂度是O(KN) public class Solution { ListNode mergeTwoLists(ListNode list1, ListNode list2) { Lis…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这道题让我们合并k个有序链表,之前我们做过一道Merge Two Sorted Lists 混合插入有序链表,是混合插入两个有序链表.这道题增加了难度,变成合并k个有序链表了,但是不管合并几个,基本还是要两两合并.那么我们首先考虑的方法是能不能利用之前那道题的解法来解答此题.答案是肯定的,但是需要修改…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. [解题思路] 以前的解法的时间复杂度过高,通过在网上搜索,得到优化的时间复杂度:O(n*lgk) 维护一个大小为k的最小堆,每次得到一个最小值,重复n次 /** * Definition for singly-linked list. * public class ListNode { * int v…
题目链接 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 合并k个有序的链表,我们假设每个链表的平均长度是n.这一题需要用到合并两个有序的链表子过程 算法1: 最傻的做法就是先1.2合并,12结果和3合并,123结果和4合并,…,123..k-1结果和k合并,我们计算一下复杂度. 1.2合并,遍历2n个节点 12结果和3合并,遍历3n个节点 123…
Discription: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Subscribe to see which companies asked this question. 思路:其实就是归并排序的最后一步归并操作.思想是递归分治,先把一个大问题分成2个子问题,然后对2个子问题的解进行合并.经过一次遍历就能找出已经有序的序列.就算是题目中给…
题意 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 将K个排好序的链表合并成一个 解法 和之前合并两个有序链表那题不同,那题用的是两个指针来分别记录两个链表中的位置,将小的那个插入新链表然后指针右移,有点像归并排序时用到的方法.这题如果用K个指针来记录的话,每次需要找出最小的那个值,比较麻烦,所以采用的优先队列,首先将所有链表的第一个值入队,然后…
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思路:这题最容易想到的是,(假设有k个链表)链表1.2合并,然后其结果12和3合并,以此类推,最后是123--k-1和k合并.至于两链表合并的过程见merge two sorted lists的分析.复杂度的分析见JustDoIT的博客.算法复杂度:假设每个链表的平均长度是n,则1.2合并,遍历2n个…