Aggressive cows(二分法)】的更多相关文章

/* 二分法的应用:最大化最小值 POJ2456 Aggressive cows Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 18125 Accepted: 8636 Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight li…
Aggressive cows Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 28666 Accepted: 13146 Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,-,xN…
Aggressive cows 二分,关键是转化为二分! #include <cstdio> #include <algorithm> ; ; int N, C; int a[maxN]; using namespace std; bool judge(int x) { ; ; i < C;i++) { ; while (ctr < N && (a[ctr]-a[s] < x)) { ctr++; } if (ctr==N) { return fa…
Aggressive cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5436   Accepted: 2720 Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,...…
Aggressive cows Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11192   Accepted: 5492 Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a straight line at positions x1,..…
最小最大...又是经典的二分答案做法.. -------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm> #include<iostream>   #define rep( i , n ) for( int i = 0 ; i < n ; ++i ) #def…
疯牛 时间限制:1000 ms  |  内存限制:65535 KB 难度:4   描述 农夫 John 建造了一座很长的畜栏,它包括N (2 <= N <= 100,000)个隔间,这些小隔间依次编号为x1,...,xN (0 <= xi <= 1,000,000,000).但是,John的C (2 <= C <= N)头牛们并不喜欢这种布局,而且几头牛放在一个隔间里,他们就要发生争斗.为了不让牛互相伤害.John决定自己给牛分配隔间,使任意两头牛之间的最小距离尽可能的…
1734: [Usaco2005 feb]Aggressive cows 愤怒的牛 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 217  Solved: 175[Submit][Status][Discuss] Description Farmer John has built a new long barn, with N (2 <= N <= 100,000) stalls. The stalls are located along a st…
Aggressive cows http://poj.org/problem?id=2456 N间小屋,M头牛,使得牛跟牛之间的距离最远,以防止牛打架. 2<=N<=100000 2<=M<=N 0 <=xi<=109 ////////////////////////////////////////////////////////////// C(d):=可以安排牛的位置使得任意两头牛的间距都不小于d 使用二分搜索法解决: //参考文献:挑战程序设计大赛(第二版)/**…
poj 2456 Aggressive cows && nyoj 疯牛 最大化最小值 二分 题目链接: nyoj : http://acm.nyist.net/JudgeOnline/problem.php?pid=586 poj : http://poj.org/problem?id=2456 思路: 二分答案,从前到后依次排放m头牛的位置,检查是否可行 代码: #include <iostream> #include <algorithm> #include &…