HDOJ(HDU).2844 Coins (DP 多重背包+二进制优化) 题意分析 先把每种硬币按照二进制拆分好,然后做01背包即可.需要注意的是本题只需要求解可以凑出几种金钱的价格,而不需要输出种数.因此用0表示不可以,1表示可以.最后对dp数组扫描一遍即可. 代码总览 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 100…

HDOJ(HDU).3466 Dividing coins ( DP 01背包 无后效性的理解) 题意分析 要先排序,在做01背包,否则不满足无后效性,为什么呢? 等我理解了再补上. 代码总览 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define nmax 505 #define nn 505*100 using namespace std;…

Dividing coins It's commonly known that the Dutch have invented copper-wire. Two Dutch men were fighting over a nickel, which was made of copper. They were both so eager to get it and the fighting was so fierce, they stretched the coin to great lengt…

1068 Find More Coins (30)(30 分) Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a speci…

Coins Accepted : 120   Submit : 305 Time Limit : 1000 MS   Memory Limit : 65536 KB Coins Problem Description: Duoxida buys a bottle of MaiDong from a vending machine and the machine give her n coins back. She places them in a line randomly showing he…

Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8800    Accepted Submission(s): 5991 Problem Description People in Silverland use square coins. Not only they have square shapes but…

dp[i][j]表示前i种硬币中取总价值为j时第i种硬币最多剩下多少个,-1表示无法到达该状态. a.当dp[i-1][j]>=0时,dp[i][j]=ci; b.当j-ai>=0&&dp[i-1][j-ai]>0时,dp[i][j]=dp[i-1][j-ai]-1; c.其他,dp[i][j]=-1 Source Code Problem: User: BMan Memory: 1112K Time: 1547MS Language: G++ Result: Accep…

题意: 给定一堆硬币,然后将他们分成两部分,使得两部分的差值最小;输出这个最小的差值. 思路: 想了好久都没想到一个合适的状态转移方程.后面看了别人的题解后,才知道能够转成背包问题求解. 我们将全部的硬币和的一半作为背包容量,然后将硬币的代价看成其本身的面值.然后背包中能装的最大容量 就是当中一个人分得硬币数. 代码例如以下: #include<iostream> #include<cstdio> #include<cstring> using namespace st…

https://www.codechef.com/problems/ANUCBC n个数字,选出其一个子集.求有多少子集满足其中数字之和是m的倍数.n $\le$ 100000,m $\le$ 100,最多90组数据 傻逼题模数取什么1e9+9毁我一节课该死煞笔提 [15:13:47]刚刚心塞了一会儿出去跑了几步好点了,然后发现好像是生物老师在艺术楼走廊上给人讲题(今天好像有学校给成绩好的单独上课之类的活动,好多同学都来了艺术楼的一个教室了和机房隔一个拐角........) #include <…

题意: n个硬币摆成一排,问有连续m个正面朝上的硬币的序列种数. 很明显的DP题.定义状态dp[i][1]表示前i个硬币满足条件的序列种数.dp[i][0]表示前i个硬币不满足条件的序列种数. 那么显然有dp[i][1]=dp[i-1][1]*2+dp[i-1-m][0]. 如果前i-1个硬币满足条件,那么第i个硬币无论怎么样都满足条件.如果前i-1-m个硬币不满足条件,那么只需要再添加m个正面朝上的硬币即可. dp[i][0]=2^i-dp[i][1]. 于是最后的答案就是dp[n][1].…

http://acm.hdu.edu.cn/showproblem.php?pid=2844 这个题目是一个多重背包转化成01背包 题意: Whuacmers拥有bi个面值为ai的硬币,现在他要用这些硬币买价格不超过m的一个物品,问你最多能刚好能用硬币付钱的物品价格有几个(即该价格能用这些硬币凑出来). 思路: 看到多重背包问题,第一时间想到的是转化为01背包来做,即我们把这个物品能选取多次当成有多个相同的物品给我们选取,复杂度是o(m*(bi的和)),根据题目给出的数据范围,这个方法的复杂度是…

最后更新 这个题做得也不好,dp[n]尝试写了几下,不太对. 应该是类似于gem theory的题. 当只有1个硬币剩下的时候直接拿走,不BB. 剩俩的时候也都拿了.. dp[n]表示剩下多少个硬币. 轮到我们拿第i个硬币的时候,有2种情况: 我们拿这个 i . 对手选择拿1个,就是第i+1个,然后第i+ 2轮到我们,我们再决定. 对手选择拿2个,i+1和i+2, 然后i+3轮到我们. 我们拿这个i,再拿下一个i+1. 对手选择拿1个,就是第i+2, 然后i+3轮到我们. 对手选择拿2个,i+2…

Eva loves to collect coins from all over the universe, including some other planets like Mars. One day she visited a universal shopping mall which could accept all kinds of coins as payments. However, there was a special requirement of the payment: f…

https://leetcode.com/problems/coin-change/ You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot…

题目 题目:CoinChange 有面额不等的coins,数量无限,要求以最少的\(coins\)凑齐所需要的\(amount\). 若能,返回所需的最少coins的数量,若不能,返回-1. Example 1: coins = [1, 2, 5], amount = 11 return 3 (11 = 5 + 5 + 1) Example 2: coins = [2], amount = 3 return -1. 无法用贪心做,例如:coins = [5,6,10], amount = 11…

mycode 我开始错误的思路:先用大钱除总钱数来保证 fewest number of coins,当最后剩下的amount小于最小币值的货币时,就说明return -1,但是这样想是有问题的!!! 例如:[1,4,5]   12=5*2+2    12 =5*2 + 1*2 用了4枚,但是12 = 4*3 因为还有下一步,也就是用次大的币值去重复这个步骤!!而且也不能直接去使用次大的,而是先把最大币值的数目-1,-2,-3....依次看 参考: 思路:类似于上一个62.unique path…

Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values o…

  用硬币换钱 题目大意:就是有面值为A1,A2,A3....的硬币,各有C1,C2,C3...的数量,问在钱数为m的范围内,能换多少钱?(不找零) 这题看名字就知道是完全背包,但是这题又有点不一样,因为这题的硬币数不是无限的,所以我们要用点特殊的思路 因为这题要我们求的是可以整换的钱的面值数,我们只要保证位置合法就可以了,所以dp矩阵内我们可以以面值数的剩余量为dp量,对于j<面值的位置,我们全部设置为当前面值的硬币数量,当j>=面值时,我们考虑两个位置:1:当上一个位置的这个位置合法(也就…

Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and found there were some coins.He decided to buy a very nice watch in a nearby shop. He wanted to pay the exact pri…

题意大概是:给出N个硬币, 面值为a_i, 问要凑成X元哪些硬币是不可或缺的.1 ≤ N ≤ 200, 1 ≤ x ≤ 10^4 直接枚举, 然后就是01背包了. 为了不让复杂度多乘个N, 我们就从左往右, 从右往左分别dp一次.这样判断一个硬币就是O(X).总时间复杂度O(NX) ----------------------------------------------------------------------------- #include<bits/stdc++.h>   usi…

Language: Default Coins Time Limit: 3000MS   Memory Limit: 30000K Total Submissions: 30047   Accepted: 10195 Description People in Silverland use coins.They have coins of value A1,A2,A3...An Silverland dollar.One day Tony opened his money-box and fou…

I - Coins Time Limit: 2 sec / Memory Limit: 1024 MB Score : 100100 points Problem Statement Let NN be a positive odd number. There are NN coins, numbered 1,2,…,N1,2,…,N. For each ii (1≤i≤N1≤i≤N), when Coin ii is tossed, it comes up heads with probabi…

[CF944G]Coins Exhibition 题意:Jack去年参加了一个珍稀硬币的展览会.Jack记得一共有 $k$ 枚硬币,这些硬币排成一行,从左到右标号为 $1$ 到 $k$ ,每枚硬币是正面朝上的或是反面朝上的.但是Jack不记得每枚硬币具体是正面朝上还是反面朝上了.但是Jack隐约记得,在某些区间里,至少有一枚正面朝上的:以及在某些区间里,至少有一枚反面朝上的.现在Jack想知道,有多少种可能的硬币序列,满足他所记得的所有条件.两个序列被认为是不同的,当且仅当至少存在一个位置 $i…

一开始没多想,虽然注意到数据N<=10^4的范围,想PAT的应该不会超时吧,就理所当然地用dfs做了,结果最后一组真的超时了.剪枝啥的还是过不了,就意识到肯定不是用dfs做了.直到看到别人说用01背包的思路,果真好久没做题了智力水平下降,且原本dp就是我的弱项,压根就没把这题往dp上去想额... (http://www.liuchuo.net/archives/2323) 题意:从n个硬皮中选取方案,使得总和价值正好为m,如果有多种,方案为排列最小的那个. 可以把硬币看成w=v(即容量=价值)的…

Coins Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 91   Accepted Submission(s) : 36 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Whuacmers use coins.They have c…

D - Bags and Coins 思路:我们可以这样构造,最大的那个肯定是作为以一个树根,所以我们只要找到一个序列a1 + a2 + a3 .... + ak 并且ak为 所有点中最大的那个,那么我们a1, a2, a3..., ak-1 作为单独的点,其他没有涉及到的点套在ak的里面. 现在问题变成了找出a1, a2, a3, a4, ... , ak. 可以用bitset优化普通dp,因为要找路径,空间开不下,所以需要分段. #include<bits/stdc++.h> #defin…

Q: 既是多重背包, 还是找零问题, 怎么处理? A: 题意理解有误, 店主支付的硬币没有限制, 不占额度, 所以此题不比 1252 难多少 Description Farmer John has gone to town to buy some farm supplies. Being a very efficient man, he always pays for his goods in such a way that the smallest number of coins change…

Square Coins Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9903    Accepted Submission(s): 6789 Problem Description People in Silverland use square coins. Not only they have square shapes but…

Problem Description People in Silverland use square coins. Not only they have square shapes but also their values are square numbers. Coins with values of all square numbers up to 289 (=17^2), i.e., 1-credit coins, 4-credit coins, 9-credit coins, ...…

Alice and Bob are playing a simple game. They line up a row of nn identical coins, all with the heads facing down onto the table and the tails upward. For exactly mm times they select any kk of the coins and toss them into the air, replacing each of…