094 Binary Tree Inorder Traversal 中序遍历二叉树

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094 Binary Tree Inorder Traversal 中序遍历二叉树

给定一个二叉树,返回其中序遍历.例如:给定二叉树 [1,null,2,3], 1 \ 2 / 3返回 [1,3,2].说明: 递归算法很简单,你可以通过迭代算法完成吗?详见:https://leetcode.com/problems/binary-tree-inorder-traversal/description/ Java实现: 递归实现: /** * Definition for a binary tree node. * public class TreeNo…

Leetcode 94. Binary Tree Inorder Traversal (中序遍历二叉树）

Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: Recursive(递归) solution is trivial, could you do it iteratively(迭代)? 思路: 解法一:用递归方法很简单, (1)如果root为空,则返回…

[LeetCode] Binary Tree Inorder Traversal 中序排序

Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what "{1,#,2,3}" means? > re…

[LeetCode]题解（python）：094 Binary Tree Inorder Traversal

题目来源 https://leetcode.com/problems/binary-tree-inorder-traversal/ iven a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. 题意分析 Input:tree Output: inorder traversal Cond…

Java for LeetCode 094 Binary Tree Inorder Traversal

解题思路: 中序遍历,左子树-根节点-右子树 JAVA实现如下: public List<Integer> inorderTraversal(TreeNode root) { List<Integer> list = new ArrayList<Integer>(); if(root==null) return list; if (root.left != null) list.addAll(inorderTraversal(root.left)); list.add(…

LeetCode OJ：Binary Tree Preorder Traversal（前序遍历二叉树）

Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3} 1 \ 2 / 3 return [1,2,3]. 前序遍历二叉树,只不过题目的要求是尽量不要使用递归,当然我还是先用递归写了一个: /** * Definition for a binary tree node. * struct TreeNode { * int val…