[题解]Painting Fence 分治模板.贪心加分治.直接\(O(n^2logn)\)分治过去.考虑一块联通的柱形是子问题的,是递归的,贪心分治就可.记得对\(r-l+1\)取\(min\). 上好看的代码 #include<bits/stdc++.h> #define RP(t,a,b) for(register int (t)=(a),edd_=(b);t<=edd_;++t) #define DRP(t,a,b) for(register int (t)=(a),edd_=(…

Codeforces Round #256 (Div. 2) C C. Painting Fence time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion d…

C. Painting Fence time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion decided to paint his old fence his…

C. Painting Fence Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion decided to paint his old fence his favorite color, orange. The fence is represented as n vertical planks, put in a row. Adjacent planks have no…

C. Painting Fence time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion decided to paint his old fence his…

题目链接:http://codeforces.com/problemset/problem/448/C C. Painting Fence time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Bizon the Champion isn't just attentive, he also is very hardworking. B…

递归.分治. . . C. Painting Fence time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion decided to paint his ol…

Painting Fence Time Limit:1000MS     Memory Limit:524288KB     64bit IO Format:%I64d & %I64u Submit Status Description Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion decided to paint his old fence his favorit…

[题解]Fence(单调队列) POJ - 1821 题目大意 有\(k\)个粉刷匠,每个粉刷匠一定要粉刷某个位置\(S_i\),一个粉刷匠可以粉刷至多\(l_i\)个位置(必须连续\(l_i\)互不相同),一个粉刷匠粉刷一个位置要收\(p_i\)元,问怎么安排可以使得粉刷匠赚的钱最大. \(dp(i,j)\)考虑了前\(i\)个人,考虑了前\(j\)个位置的最大值,转移是这样的: \[ dp(i,j)=\max\{\max\{dp(i-1,k)+(j-k)\times p_i\},dp(i-1…

C. Painting Fence time limit per test 1 second memory limit per test 512 megabytes input standard input output standard output Bizon the Champion isn't just attentive, he also is very hardworking. Bizon the Champion decided to paint his old fence his…