You can Solve a Geometry Problem too                                         Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)                                         Problem Description Many geometry(几何)problems wer…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12959    Accepted Submission(s): 6373 Problem Description Many geometry(几何)problems were designed in the ACM/…

http://acm.hdu.edu.cn/showproblem.php?pid=1086 分析:简单计算几何题,相交判断直接用模板即可. 思路:将第k条直线与前面k-1条直线进行相交判断,因为题目中不排除多条直线相交于同一个点的重复情况. 代码: #include <iostream> #include <stdio.h> #include <string.h> #include <algorithm> #include <queue> #i…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6837 Accepted Submission(s): 3303 Problem Description Many geometry(几何)problems were designed in the ACM/ICPC. A…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9596    Accepted Submission(s): 4725 Problem Description Many geometry(几何)problems were designed in the ACM/I…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10204    Accepted Submission(s): 5042 Problem Description Many geometry(几何)problems were designed in the ACM/…

称号: You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 145 Accepted Submission(s): 100   Problem Description Many geometry(几何)problems were designed in the ACM/IC…

pid=1086">You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6997    Accepted Submission(s): 3385 Problem Description Many geometry(几何)problems were designe…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 199    Accepted Submission(s): 132   Problem Description Many geometry(几何)problems were designed in the ACM/…

http://acm.hdu.edu.cn/showproblem.php?pid=1086 You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8861    Accepted Submission(s): 4317 Problem Description Many…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6340    Accepted Submission(s): 3064 Problem Description Many geometry(几何)problems were designed in the ACM/I…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6425    Accepted Submission(s): 3099 Problem Description Many geometry(几何)problems were designed in the ACM/I…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6932    Accepted Submission(s): 3350 Problem Description Many geometry(几何)problems were designed in the ACM/I…

You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13549    Accepted Submission(s): 6645 Problem Description Many geometry(几何)problems were designed in the ACM/…

Problem Description Many geometry(几何)problems were designed in the ACM/ICPC. And now, I also prepare a geometry problem for this final exam. According to the experience of many ACMers, geometry problems are always much trouble, but this problem is ve…

Problem Description Many geometry(几何)problems were designed in the ACM/ICPC. And now, I also prepare a geometry problem for this final exam. According to the experience of many ACMers, geometry problems are always much trouble, but this problem is ve…

链接:传送门 题意:给出 n 个线段找到交点个数 思路:数据量小,直接暴力判断所有线段是否相交 /************************************************************************* > File Name: hdu1086.cpp > Author: WArobot > Blog: http://www.cnblogs.com/WArobot/ > Created Time: 2017年05月07日 星期日 23时34…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1086 判断两条线段是否有交点,我用的是跨立实验法: 两条线段分别是A1到B1,A2到B2,很显然,如果这两条线段有交点,那么可以肯定的是: A1-B1,A2-B1这两个向量分别在B2-B1的两边,判断是不是在两边可以用向量的叉积来判断,这里就不说了,同理B1-A1,B2-A1在A2-A1的两边,当同时满足这两个条件时,说明这两条线段是有交点的. #include<cstdio> #include&…

数学题,证明AB和CD.只需证明C.D在AB直线两侧,并且A.B在CD直线两侧.公式为:(ABxAC)*(ABxAD)<= 0 and(CDxCA)*(CDxCB)<= 0 #include <stdio.h> #define MAXNUM 105 typedef struct { double x1, y1; double x2, y2; } line_st; line_st lines[MAXNUM]; int cal(int i, int j) { double ab_x,…

题目:给出一些线段,判断有几个交点. 问题:如何判断两条线段是否相交? 向量叉乘(行列式计算):向量a(x1,y1),向量b(x2,y2): 首先我们要明白一个定理:向量a×向量b(×为向量叉乘),若结果小于0,表示向量b在向量a的顺时针方向:若结果大于0,表示向量b在向量a的逆时针方向:若等于0,表示向量a与向量b平行.(顺逆时针是指两向量平移至起点相连,从某个方向旋转到另一个向量小于180度).如下图: 在上图中,OA×OB = 2 > 0, OB在OA的逆时针方向:OA×OC = -2 <…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6242 思路:当 n == 1 时 任取一点 p 作为圆心即可. n >= 2 && n < 5 时 此时有可能出现所有点共线,所以取任意俩点间中点作为圆的圆心. n >= 5 保证了有解.所以不可能有所有点共线的情况,随机取三个点在正解圆上的概率是 1/8,还是蛮大的.... 外学了下随机算法的写法....时间种子 time(0)要强制转成int,不然会WA,不造为啥....…

原题: Description Mike wants to prepare for IMO but he doesn't know geometry, so his teacher gave him an interesting geometry problem. Let's define f([l, r]) = r - l + 1 to be the number of integer points in the segment [l, r] with l ≤ r (say that ). Y…

Mike and Geometry Problem 题目链接: http://acm.hust.edu.cn/vjudge/contest/121333#problem/I Description Mike wants to prepare for IMO but he doesn't know geometry, so his teacher gave him an interesting geometry problem. Let's define f([l, r]) = r - l + 1…

Problem B. Geometry ProblemTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=88926#problem/B Description Peter is studying in the third grade of elementary school. His teacher of geometry often gives h…

E. Mike and Geometry Problem 题目连接: http://www.codeforces.com/contest/689/problem/E Description Mike wants to prepare for IMO but he doesn't know geometry, so his teacher gave him an interesting geometry problem. Let's define f([l, r]) = r - l + 1 to…

E. Mike and Geometry Problem time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Mike wants to prepare for IMO but he doesn't know geometry, so his teacher gave him an interesting geometry pro…

传送门:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5861 Little Sub and his Geometry Problem Time Limit: 4 Seconds      Memory Limit: 65536 KB Little Sub loves math very much, and has just come up with an interesting problem when he is wor…

任意门:http://codeforces.com/contest/689/problem/E E. Mike and Geometry Problem time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Mike wants to prepare for IMO but he doesn't know geometry, so…

题目链接: E. Mike and Geometry Problem time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Mike wants to prepare for IMO but he doesn't know geometry, so his teacher gave him an interesting geomet…

Geometry Problem Time Limit: 2000/1000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others)     Special Judge SubmitStatus Problem Description       Peter is studying in the third grade of elementary school. His teacher of geometry often gives…