[LeetCode] Rotated Digits 旋转数字

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[LeetCode] Rotated Digits 旋转数字

X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X. Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit after rotat…

LeetCode 788. Rotated Digits (旋转数字)

X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X. Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit after rotat…

Leetcode788.Rotated Digits旋转数字

我们称一个数 X 为好数, 如果它的每位数字逐个地被旋转 180 度后,我们仍可以得到一个有效的,且和 X 不同的数.要求每位数字都要被旋转. 如果一个数的每位数字被旋转以后仍然还是一个数字, 则这个数是有效的.0, 1, 和 8 被旋转后仍然是它们自己:2 和 5 可以互相旋转成对方:6 和 9 同理,除了这些以外其他的数字旋转以后都不再是有效的数字. 现在我们有一个正整数 N, 计算从 1 到 N 中有多少个数 X 是好数? 示例: 输入: 10 输出: 4 解释: 在[1, 10]中有四个…

788. Rotated Digits 旋转数字

［抄题］: X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X. Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit after…

[LeetCode] Add Digits 加数字

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. Follow up: Could you do it without an…

leetCode题解之旋转数字

1.题目描述 X is a good number if after rotating each digit individually by 180 degrees, we get a valid number that is different from X. Each digit must be rotated - we cannot choose to leave it alone. A number is valid if each digit remains a digit afte…