题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5855 Less Time, More profit Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/65536 K (Java/Others) 问题描述 The city planners plan to build N plants in the city which has M shops. Each shop needs p…

二分t+最大权闭合图. 很显然二分那个t作为limit.每一个limit下,有一些边不能用了,然后要知道这种情况下怎么选点获得的价值最大. 这么想:一个shop想获得收益,就必须选择某一些plant,问题就转化成了最大权闭合图. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #incl…

Less Time, More profit Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description The city planners plan to build N plants in the city which has M shops. Each shop needs products from some plants to make p…

意甲冠军: 特定n小点的树权. 以下n每一行给出了正确的一点点来表达一个销售点每只鸡价格的格 以下n-1行给出了树的侧 以下Q操作 Q行 u, v, val 从u走v,程中能够买一个鸡腿,然后到后面卖掉,输出max(0, 最大的收益) 然后给[u,v]路径上点点权+=val 思路: 树链剖分裸题.记录区间的最大最小值,→走的答案和←走的答案. 官方题解:点击打开链接 #pragma comment(linker, "/STACK:1024000000,1024000000") #inc…

题目大意: 给出一棵树.每一个点有商店.每一个商店都有一个价格,Yaoge每次从x走到y都能够在一个倒卖商品,从中得取利益.当然,买一顶要在卖之前.可是没次走过一条路,这条路上的全部商品都会添加一个v. 输出每次的最大利益. 思路分析: 非常easy想到树链剖分,但是关键在于怎样维护这样一个变量.使得每次都要让买的再卖的前面. 维护变量 ltr 和 rtl .表示从左去右和从右去左. 剖分熟练的时候.推断x 和 y的深度,一步一步往上爬. 然后维护区间最大值和最小值.爬的时候更新答案. ...4…

Yaoge’s maximum profit Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) 题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=5052 Problem Description Yaoge likes to eat chicken chops late at night. Yaoge has eaten too ma…

Less Time, More profit Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 468    Accepted Submission(s): 172 Problem Description The city planners plan to build N plants in the city which has M sho…

题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=5855 Description The city planners plan to build N plants in the city which has M shops. Each shop needs products from some plants to make profit of proi units. Building ith plant needs investment o…

ACboy needs your help Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4912    Accepted Submission(s): 2651 Problem Description ACboy has N courses this term, and he plans to spend at most M days…

F - City Game Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1505 Appoint description: Description Bob is a strategy game programming specialist. In his new city building game the gaming enviro…