Description Diophantus of Alexandria was an egypt mathematician living in Alexandria. He was one of the first mathematicians to study equations where variables were restricted to integral values. In honor of him, these equations are commonly called d…

Problem Description To improve the organization of his farm, Farmer John labels each of his N (1 <= N <= 5,000) cows with a distinct serial number in the range 1..20,000. Unfortunately, he is unaware that the cows interpret some serial numbers as be…

Diophantus of Alexandria Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2269    Accepted Submission(s): 851 Problem Description Diophantus of Alexandria was an egypt mathematician living in Ale…

题目链接:hdu 1299 Diophantus of Alexandria 题意: 给你一个n,让你找1/x+1/y=1/n的方案数. 题解: 对于这种数学题,一般都变变形,找找规律,通过打表我们可以发现这个答案只与这个数的因子有关. n=a1^p1*a2^p2*...*an^pn ans=((1+2*p1)*(1+2*p2)*...*(1+2*pn)+1)/2 #include<bits/stdc++.h> #define F(i,a,b) for(int i=a;i<=b;++i)…

Diophantus of Alexandria was an egypt mathematician living in Alexandria. He was one of the first mathematicians to study equations where variables were restricted to integral values. In honor of him, these equations are commonly called diophantine e…

hdoj 1299 Diophantus of Alexandria 链接:http://acm.hdu.edu.cn/showproblem.php?pid=1299 题意:求 1/x + 1/y = 1/n (x <= y) 的组数. 思路:转化为一个数的因子个数. 因为x,y,z 都是整数,令 y = n+k (倒数和相等,x,y 明显大于 n),带入式子可得 x = n*n / k + n :所以 x 的组数就与k相关了,只要 k 满足是 n*n 的约数,组数就 +1.假设 n = (p…

HDU 2098 分拆素数和(素数) http://acm.hdu.edu.cn/showproblem.php?pid=2098 题意: 给你一个偶数,问你这个偶数有多少种方式能由两个不同的素数构成? 分析: 首先求出10000以内的全部素数. 假设这个偶数X能有两个不同的素数构成,那么一定一个小于(X/2-1). 仅仅要从小到大枚举这个比較小的素数a.然后看看X-b是否是素数就可以得到一种组合方式. 依次统计全部组合方式就可以. AC代码: #include<cstdio> #includ…

Diophantus of Alexandria Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3210    Accepted Submission(s): 1269 Problem Description Diophantus of Alexandria was an egypt mathematician living in Al…

Diophantus of Alexandria Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3242 Accepted Submission(s): 1287 Problem DescriptionDiophantus of Alexandria was an egypt mathematician living in Alexandri…

HDU 2098 分拆素数和 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768K (Java/Others) [题目描述 - Problem Description] 把一个偶数拆成两个不同素数的和,有几种拆法呢? [输入 - Input] [输出 - Output] 输入包含一些正的偶数,其值不会超过10000,个数不会超过500,若遇0,则结束. 对应每个偶数,输出其拆成不同素数的个数,每个结果占一行. [输入样…