http://acm.hdu.edu.cn/showproblem.php?pid=2289 二分法解题. 这个题很恶心...一开始测试样例都不能过,这个π一开始取3.1415926结果是99.999026,改为3.1414927,结果是99.999023..我就发现这个π对结果影响很大,这个题对π的精度要求也比较高...然后我的π就改为3.1415926536... 一开始判断跳出二分的条件是结果差值小于0.000000001,发现超时,改为0.01后还是超时...无语了...然后仔细想想,题…

这道题目.运营商做数学题?算上两个子主题做?顶多算一个水主要议题... 首先,没有实际的二分法,但是,我们发现了一个新的解决方案,以取代二分法. 若果按照i从0,每次添加0.00000001我一直枚举h如果,绝对逼暂停.枚举太大 然而,它可以分为两个步骤: #include<cstdio> #include<cmath> #define pai acos(-1.0) double r1,r2,h,v; double get_v(double temp) { double rr=r1…

Cup Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 8942    Accepted Submission(s): 2744 Problem Description The WHU ACM Team has a big cup, with which every member drinks water. Now, we know th…

Cup Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6684    Accepted Submission(s): 2062 Problem Description The WHU ACM Team has a big cup, with which every member drinks water. Now, we know th…

Cup Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7077    Accepted Submission(s): 2177 Problem Description The WHU ACM Team has a big cup, with which every member drinks water. Now, we know th…

<题目链接> 题目大意: 一个圆台型的杯子,它的上底半径和下底半径已经给出,并且给出它的高度,问你,体积为V的水倒入这个杯子中,高度为多少. 解题分析: 就是简单的二分答案,二分枚举杯中水的高度,然后根据几何计算出该高度下,水的上半径,然后计算出该高度下水的体积,在与实际水的体积进行比较,从而确定最终的答案. #include <cstdio> #include <cstring> #include <cmath> const double PI=acos(…

题目传送门 /* 二分搜索:枚举高度,计算体积与给出的比较. */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> using namespace std; ; const int INF = 0x3f3f3f3f; ; const double PI = acos (-1.0); double r, R, H, V; double x; double ca…

题目传送门:https://vjudge.net/problem/HDU-2289 题意:有一个上口小于底部的圆台形水杯,告诉我们水的体积求水高度. 思路:利用高中数学知识求rr然后二分求h,具体化简过程见下图. 1 //#include<bits/stdc++.h> 2 #include<time.h> 3 #include <set> 4 #include <map> 5 #include <stack> 6 #include <cma…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2289 大意是 一个Cup,圆台形,给你它的顶部圆的半径,底部圆的半径,杯子的高度,和此时里面装的水的体积,求水的高度. 这道题好在能够锻炼算法思维,或者说形成算法思维. 这是一道二分逼近求值的应用 题目已经给定杯子的高度是0~100,故在这个范围内进行二分,但走了涉及到还有小数的问题,故可以取一个精度较高的误差值 来作为二分的条件,二分一次,以这个值作为水的高度求出水的体积与实际值比较一次,当误差不…

Cable master Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1428    Accepted Submission(s): 522 Problem Description Inhabitants of the Wonderland have decided to hold a regional programming con…